If the perimeter of the equilateral triangle is 18 cm then the width of the rectangle be 11.2 cm.
Given that the perimeter of the equilateral triangle be 18 cm and the perimeter of all the three triangles be 46.4 cm.
We are required to find the width of the rectangle.
Rectangle is basically the shape which is having opposite sides equal to each other.
Perimeter of equilateral triangle=3 *side
3* side=18
side=18/3
side=6
Since it is on the length of the rectangle so the length of rectangle be
6 cm.
Perimeter of all the three triangles=2*width of the rectangle+1 length+perimeter of 1 equilateral triangle.
T1 and T2 are the other triangles.
Suppose the width of the rectangle be x.
Perimeter=2*x+6+18
46.4=2x+24
2x=46.4-24
2x=22.4
x=11.2
So,the width of the rectangle is equal to 11.2 cm.
Hence if the perimeter of the equilateral triangle is 18 cm then the width of the rectangle be 11.2 cm.
Learn more about perimeter at brainly.com/question/19819849
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Answer: 5.5km
Step-by-step explanation:
The scale given 1 : 25 000 , and it was said that on the map , the distance between two railway stations is 22 cm , this means that the scale of the map is 1: 25000 cm.
The scale 1 : 25 000 means that each centimeters on the map represent 25 ,000 in real life ,therefore , to calculate the real distance between the two railway station , we have
25,000 X 22
= 550000 cm
To convert this to km
Recall that
1 km = 100,000 cm
Therefore we will divide the answer by 100,000 , that is
550000/100000
= 5.5 km
Therefore , the real distance between the two railway stations is 5.5km
Answer:
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Step-by-step explanation:
Answer:
10
Step-by-step explanation: