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siniylev [52]
3 years ago
12

G=xc, for xThis is a Math problem based kn literal equations

Mathematics
1 answer:
Vilka [71]3 years ago
7 0
Divide sides by c

g/c=x.
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3x + 5y = 7<br> -3x - 2y = -1
Oksanka [162]

Answer:

(-1,2) y=2 x=-1

Step-by-step explanation:

This is a system of equations and in this you see there is 3x and negative three x. To solve this you need tp get rid of one of the variables. so we can add the two equations together to get 3y=6. This means that y=2 if we divide by 3 on both sides. Then we just plug 3 in for y and we get 3x+10=7. We subtract 10 on both sides to get 2x=-3 which means x=-1.

6 0
3 years ago
5/8(x-1/3)=5/12 can someone help me figure out what x is?
eimsori [14]
Solve for x:(5 (x - 1/3))/(8) = 5/12
Put each term in x - 1/3 over the common denominator 3: x - 1/3 = (3 x)/3 - 1/3:(5 (3 x)/3 - 1/3)/(8) = 5/12
(3 x)/3 - 1/3 = (3 x - 1)/3:(5 (3 x - 1)/3)/(8) = 5/12
3×8 = 24:(5 (3 x - 1))/24 = 5/12
Multiply both sides of (5 (3 x - 1))/24 = 5/12 by 24/5:(24×5 (3 x - 1))/(5×24) = (24×5)/(5×12)
(24×5)/(5×12) = (24×5)/(5×12):(24×5 (3 x - 1))/(5×24) = (24×5)/(5×12)
(24×5 (3 x - 1))/(5×24) = (5×24)/(5×24)×(3 x - 1) = 3 x - 1:3 x - 1 = (24×5)/(5×12)
(24×5)/(5×12) = 5/5×24/12 = 24/12:3 x - 1 = 24/12
The gcd of 24 and 12 is 12, so 24/12 = (12×2)/(12×1) = 12/12×2 = 2:3 x - 1 = 2
Add 1 to both sides:3 x + (1 - 1) = 1 + 2
1 - 1 = 0:3 x = 2 + 1
2 + 1 = 3:3 x = 3
Divide both sides of 3 x = 3 by 3:(3 x)/3 = 3/3
3/3 = 1:x = 3/3
3/3 = 1:Answer:  x = 1
3 0
3 years ago
If ∠=,m angle 1 equals 71, find ∠.
cluponka [151]
Do you have a picture?
3 0
3 years ago
Read 2 more answers
Determine the commutators of the operators a and a+,where a = (x + ip)/2 ^1/2 and a+ = (x - ip)/ 2 ^1/2
Vsevolod [243]

Answer:

Given that:

a = (\frac{x+ip}{2})^{\frac{1}{2}} and a+= (\frac{x-ip}{2})^{\frac{1}{2}}

if a , a+ commutator, it obeys aa^+ = a^+a

First find:

aa^+ = (\frac{x+ip}{2})^{\frac{1}{2}} (\frac{x-ip}{2})^{\frac{1}{2}}

                = (\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}

Now;

a^+a =(\frac{x-ip}{2})^{\frac{1}{2}} (\frac{x+ip}{2})^{\frac{1}{2}} = (\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}

              =(\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}

therefore, aa^+ = a^+a which implies the operators a and a+ are commutators.    


7 0
3 years ago
How many ways can 6 people be chosen and arranged in a straight line if there are 8 people to choose from? 720 20,160 40,320 48?
Rudik [331]
The number of permutations of 8 people taken 6 at a time is given by:
8P6=\frac{8!}{(8-6)!}=20,160&#10;
5 0
3 years ago
Read 2 more answers
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