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aleksandr82 [10.1K]
3 years ago
8

Find the volume of each rectangular prism

Mathematics
2 answers:
Flura [38]3 years ago
6 0

Answer:

64

Step-by-step explanation:

L=Length

W=Width

H=Height

L=4

W=4

H=4

4 x 4 x 4

4 x 4 = 16

16 x 4 = 64

Hope this answers your question.

Dmitrij [34]3 years ago
4 0
The answer is basically just 4*4*4 so your answer is 64
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What is the range of 16,17,17,18,18,18,19,19,19,19,20,20,20,21,21,22,22,24,25,25
Aleksandr-060686 [28]

In order to find the range we first have to list the numbers from least to greatest:

16, 17, 17, 18, 18, 18, 19, 19, 19, 19, 20, 20, 20, 21, 21, 22, 22, 24, 25, 25

range = largest value - smallest value = answer

range = 25 - 16 = 9

range = 19

so, our final answer would be 19.

~ i hope this helps you have a good day/night afternoon~ ~-gabby~

7 0
4 years ago
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Expand using the distributive property 10(-4x + 2)​
sveticcg [70]

Answer:

-40x+20

Step-by-step explanation:

10 times -4x=-40x

10x2=20

8 0
3 years ago
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Whats the equation for this​
yawa3891 [41]

Answer:

x^2 + y^2 + 4x + 4y  = -119/16

Step-by-step explanation:

The axes x and y are calibrated in 0.25

If the circle is carefully considered, the radius r of the circle is:

r = -1.25 - (-2)

r = 0.75 units

The equation of a circle is given by:

(x - a)^2 + (y - b)^2 = r^2

The center of the circle (a, b) = (-2, -2)

Substituting  (a, b) = (-2, -2) and r = 0.75 into the given equation:

(x - (-2))^2 + (y - (-2))^2 = (3/4)^2\\\\(x + 2)^2 + (y + 2)^2 = (3/4)^2\\\\x^2 + 4x + 4 + y^2 + 4y + 4 = 9/16\\\\x^2 + y^2 + 4x + 4y + 8 = 9/16\\\\16x^2 + 16y^2 + 64x + 64y + 128 = 9\\\\16x^2 + 16y^2 + 64x + 64y  = -119\\\\x^2 + y^2 + 4x + 4y  = -119/16\\

5 0
3 years ago
Help please I will give brainiest​
Evgen [1.6K]

Answer:

I think number 17 is 180°

5 0
3 years ago
Read 2 more answers
A = ???? 4 −2
irinina [24]

Answer:

1. The matrix A isn't the inverse of matrix B.

2. |B|=12, |A|=12

Step-by-step explanation:

1. We want to know if matrix A is the inverse of matrix B, this means that if you do the product between B and A you have to obtain the identity matrix.

We have:

A=\left[\begin{array}{cc}4&-2\\-1&3\end{array}\right]

and

B=\left[\begin{array}{cc}3&2\\1&4\end{array}\right]

A and B are 2×2 matrices (2 rows and 2 columns), if you multiply them you have to obtain a 2×2 matrix.

Then if A is the inverse of B:

B.A=I

Where,

I=\left[\begin{array}{cc}1&0\\0&1\end{array}\right]

Observation:

If you have two matrices:

A=\left[\begin{array}{cc}a&b\\c&d\end{array}\right]\\and\\B=\left[\begin{array}{cc}e&f\\g&h\end{array}\right]\\\\\\A.B=\left[\begin{array}{cc}(a.e+b.g)&(a.f+b.h)\\(c.e+d.g)&(c.f+d.h)\end{array}\right]

Now:

B.A=\left[\begin{array}{cc}3&2\\1&4\end{array}\right].\left[\begin{array}{cc}4&-2\\-1&3\end{array}\right]\\\\\\B.A=\left[\begin{array}{cc}4.3+(-2).1&4.2+(-2).4\\(-1).3+3.1&(-1).2+3.4\end{array}\right]\\\\\\B.A=\left[\begin{array}{cc}12-2&8-8\\-3+3&-2+12\end{array}\right]\\\\\\B.A=\left[\begin{array}{cc}10&0\\0&10\end{array}\right]

B.A=\left[\begin{array}{cc}10&0\\0&10\end{array}\right]\neq \left[\begin{array}{cc}1&0\\0&1\end{array}\right]=I\\\\\\B.A\neq I

Then, the matrix A isn't the inverse of matrix B.

2. If you have a matrix A:

A=\left[\begin{array}{cc}a&b\\c&d\end{array}\right]

The determinant of the matrix is:

|A|=ad-bc

Then the determinant of B is:

B=\left[\begin{array}{cc}3&2\\1&4\end{array}\right]

a=3, b=2, c=1, d=4

|B|=3.4-2.1\\|B|=12-2=10

The determinant of A is:

A=\left[\begin{array}{cc}4&-2\\-1&3\end{array}\right]

a=4, b=-2, c=-1, d=3

|A|=4.3-(-2).(-1)\\|B|=12-2=10

6 0
4 years ago
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