follow these steps:
1) y-4=7x^2
2) (y-4)/7 = x^2

so you must inverse x and y names:

Answer:
D: Sqrt 13
Step-by-step explanation:
I just did it on edg. 2020
Answer:
y = -1/3x + 3 2/3
Step-by-step explanation:
step 1. find the slope of the given line
y2-y1/x2-x1 2 - 4/ 3 + 3 = - 1 / 3
take the opposite of that and there is your slope
step 2. plug in the values to the following equation using the given point:
y - y1 = m ( x - x1 ) y - 4 = - 1/3 ( x + 1 )
step 3. solve for y
y-4 = -1/3(x+1)
-1/3(x) and -1/3(1) ----> y-4 = -1/3x-1/3
y-4+4 = -1/3x-1/3+4 ----> y = -1/3x + 3 2/3
<em>hope this helps. if you need more help lmk in the comments. i am in algebra two so you can trust me. Happy holidays</em>
Answer:

Step-by-step explanation:
Use the formula
to find the sum of the angles in a polygon, given <em>n</em> sides. This formula tells us the angles of this pentagon must add to 540 (
).
So, we can setup an equation:

Solve for z:
Combine like terms
Subtract 200
Divide by 5
Therefore, the value of z = 68.
Answer:
(3x+4)(5x+7)
Step-by-step explanation:
15x^2
+41x+28
Factor the expression by grouping. First, the expression needs to be rewritten as 15x^2
+ax+bx+28. To find a and b, set up a system to be solved.
a+b=41
ab=15×28=420
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 420.
1,420
2,210
3,140
4,105
5,84
6,70
7,60
10,42
12,35
14,30
15,28
20,21
Calculate the sum for each pair.
1+420=421
2+210=212
3+140=143
4+105=109
5+84=89
6+70=76
7+60=67
10+42=52
12+35=47
14+30=44
15+28=43
20+21=41
The solution is the pair that gives sum 41.
a=20
b=21
Rewrite 15x^2
+41x+28 as (15x^2
+20x)+(21x+28).
(15x^2
+20x)+(21x+28)
Factor out 5x in the first and 7 in the second group.
5x(3x+4)+7(3x+4)
Factor out common term 3x+4 by using distributive property.
(3x+4)(5x+7)