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TiliK225 [7]
3 years ago
10

In attempting to become financially organized, a person:

Mathematics
2 answers:
Y_Kistochka [10]3 years ago
5 0
The answers A and D can be true for some people but are not true generally: they depend on the people's natural organization skills.

Answer B is wrong: one needs to also consider their income, spending, savings, etc...

the correct answer is the following one: <span>C. frequently discovers the complexity of his or her financial situation. </span>
zepelin [54]3 years ago
4 0

Answer:

Only C is true.

Step-by-step explanation:

A. generally has no difficulty in deciding what courses of action should be taken. - Financial organizing is a very vast and deep term that cannot be attained in a single day. A person needs to look upon various things before being called a financially organised person. Hence, this option does not hold true.

B. only needs to evaluate items pertaining to the area of investments.- This is not fully true as the person also needs to focus on aspects that can lead to possible losses in future. The pros and cons go hand in hand.

C. frequently discovers the complexity of his or her financial situation. Yes, this is correct as a person should always weigh and rec check his financial situations.

D. usually discovers that he or she is already well organized financially. This is not true as this field is always open for improvement and no one can possibly say that he is well organised without any room for improvement.

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Sunny_sXe [5.5K]

Answer:the answer is A my friend ;)

Step-by-step explanation:

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3 years ago
Help give me the formula and the answer and plz explain so I also benefit:)
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4 0
3 years ago
Memory module consists of 9 chips. The device is designed with redundancy so that it works even if one of its chips is defective
soldier1979 [14.2K]

Answer:

a) P[C]=p^n

b) P[M]=p^{8n}(9-8p^n)

c) n=62

d) n=138

Step-by-step explanation:

Note: "Each chip contains n transistors"

a) A chip needs all n transistor working to function correctly. If p is the probability that a transistor is working ok, then:

P[C]=p^n

b) The memory module works with when even one of the chips is defective. It means it works either if 8 chips or 9 chips are ok. The probability of the chips failing is independent of each other.

We can calculate this as a binomial distribution problem, with n=9 and k≥8:

P[M]=P[C_9]+P[C_8]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)\\\\P[M]=p^{8n}(p^{n}+9(1-p^n))\\\\P[M]=p^{8n}(9-8p^n)

c)

P[M]=(0.999)^{8n}(9-8(0.999)^n)=0.9

This equation was solved graphically and the result is that the maximum number of chips to have a reliability of the memory module equal or bigger than 0.9 is 62 transistors per chip. See picture attached.

d) If the memoty module tolerates 2 defective chips:

P[M]=P[C_9]+P[C_8]+P[C_7]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1+\binom{9}{7}P[C]^7(1-P[C])^2\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])+36P[C]^7(1-P[C])^2\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)+36p^{7n}(1-p^n)^2

We again calculate numerically and graphically and determine that the maximum number of transistor per chip in this conditions is n=138. See graph attached.

6 0
4 years ago
Evaluate 3x +2y - 4z/x for x =5, y=-2,z=10
Evgen [1.6K]

3x + 2y - 4z/x for x=5, y=-2, z=10

3x + 2y - 4z/x

3(5) + 2(-2) - 4(10)/(5)

15 - 4 - 40/5

15 - 4 - 8

11 - 8

3

3 0
3 years ago
Solve for x 2/3 + 3/5x = x+5/10<br> x = –3<br> x = 2<br> x = –3 and x = 2<br> No Solution
KengaRu [80]

Answer:

c

Step-by-step explanation:

x = –3 and x = 2

4 0
3 years ago
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