Question

Gold has a latent heat fusion of 64.5 J/g. How much energy is required to melt 20.0 g of gold?

Answer 1

Answer: 1290 Joules

Explanation:

Latent heat of fusion is the amount of heat required to convert 1 mole of solid to liquid at atmospheric pressure.

Amount of heat required to fuse 1 gram of gold = 64.5 J

Mass of gold given = 20 gram

Heat required to fuse 1 g of gold = 64.5 J

Thus Heat required to fuse 20 g of gold =$\frac{64.5}{1}\times 20=1290J$

Thus 1290 Joules energy is required to melt 20.0 g of gold

Answer 2

Answer:

1290

Explanation:

dq = mass Au x heat fusion