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frez [133]
3 years ago
7

The equation of a line is given below.

Mathematics
2 answers:
makkiz [27]3 years ago
6 0
Y=3-4/3x
y-intercept is 3

disa [49]3 years ago
5 0

Answer:

y - intercept: (0,3)

slope: -4/3

Step-by-step explanation:

4x +3y = 9

3y = -4x + 9

y = -4/3x + 3

to find the y - intercept you make x = 0, so...

y = -4/3(0) + 3

y = 3

therefore y - intercept is (0,3)

to find the slope you look at your linear equation and see what number is in front of the x

so in this case -4/3 is the slope, because that's what's in front of the x

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2 + 2 what is the best answer​
Allisa [31]

Answer:

4

Step-by-step explanation

you have 2, so count 2 more

1, <u>2</u>, 3 , <em>4</em>!

4 0
3 years ago
Anna is making a square pen for her rabbit to play in. Each
melisa1 [442]

Answer:

area \: A =  {s}^{2}  \\  =  {9}^{2}  \\  A \: = 81 \: square \: feet \\ or \\ A = 81 \:  {ft}^{2}

5 0
3 years ago
Read 2 more answers
an initial amount of 2,400 grows at a rate of 12% every month. Write an exponential equation for the amount y after x months
scoray [572]

Answer:

The expression is y(x) = 2400*(1.12)^x

Step-by-step explanation:

The initial amount is:

y(0) = 2400

After the first month it is:

y(1) = y(0)*(1 + 12/100) = 2400*(1 + 0.12) = 2400*(1.12)

After the second month it is:

y(2) = y(1)*(1.12) = y(0)*(1.12)*(1.12) = y(0)*(1.12)²

After the third month it is:

y(3) = y(2)*(1.12) = y(0)*(1.12)²*(1.12) = y(0)*(1.12)³

After "x" months, we have:

y(x) = y(0)*(1.12)^x

y(x) = 2400*(1.12)^x

6 0
3 years ago
EXPLAIN THE SECOND PART.......
alexdok [17]
\tan^2\theta-\sin^2\theta=\dfrac{\sin^2\theta}{\cos^2\theta}-\sin^2\theta
=\sin^2\theta\left(\dfrac1{\cos^2\theta}-1\right)
=\sin^2\theta(\sec^2\theta-1)
=\sin^2\theta\tan^2\theta

Now if 0^\circ, then both \sin\theta>0 and \tan\theta>0. Adding two positive numbers gives another positive number, so \tan\theta+\sin\theta>0. Why this is useful will be apparent shortly.

Back to the identity:

\tan^2\theta-\sin^2\theta=\tan^2\theta\sin^2\theta

Factorizing the left hand side, we have

(\tan\theta-\sin\theta)(\tan\theta+\sin\theta)=\tan^2\theta\sin^2\theta

Now, any number squared will be positive, which means the right hand side is necessarily greater than 0.

We showed earlier that \tan\theta+\sin\theta>0. So we understand that we have

\underbrace{(\tan\theta-\sin\theta)}_?\underbrace{(\tan\theta+\sin\theta)}_+=\underbrace{\tan^2\theta\sin^2\theta}_+

The only way to multiply a number by a positive number to get yet another positive number is to have the first number also be positive, which means

\tan\theta-\sin\theta>0

and from this it follows that

\tan\theta>\sin\theta

in the provided region.
6 0
3 years ago
Your professor has just collected eight different statistics exams. If these
musickatia [10]

Answer:

It would be 1/40320

8 0
3 years ago
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