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vlada-n [284]
4 years ago
11

How many excess electrons must be distributed uniformly within the volume of an isolated plastic sphere 29.0 cmcm in diameter to

produce an electric field of 1000 N/CN/C just outside the surface of the sphere?
Physics
1 answer:
SpyIntel [72]4 years ago
4 0

Answer:

= 1.46 × 10 ¹⁰ electron

Explanation:

Given that

E, Electric field = 1000N/C

D, Diameter = 29cm

r, radius = 0.145

E = kq/r²

→ q = Er²/k

  q = (1000 × (0.145)² ) / (9 × 10⁹)

q = 2.34 × 10⁻⁹C

q = Ne

where e = 1.6 × 10⁻¹⁹

N = (2.34 × 10⁻⁹) / (1.6 × 10⁻¹⁹)

   = 1.46 × 10¹⁰ electron

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two masses are kept 2 metre apart there is gravitational force of 2 Newton what is the gravitational force when they are kept at
sukhopar [10]

Answer: 0.5N

Explanation:

Gravitational force is calculated using the formula :

F = Gm1m2/r^2

Where G is the gravitational constant (6.67 × 10^-11)

At a distance 'r' of 2metres apart:

Mass of objects are m1 and m2

Gravitational force 'F1' = 2N

Inputting values into the formula :

2 = Gm1m2 / 2^2 - - - - - (1)

At a distance 'r' of 4meters apart:

Mass of objects are m1 and m2

Gravitational force 'F2' = y

Inputting values

F2 = Gm1m2 / 4^2 - - - - - (2)

Dividing equations 1 and 2

2 = Gm1m2 / 2^2 ÷ F2 = Gm1m2 / 4^2

2 / F2 = (Gm1m2 / 4) / (Gm1m2 / 16)

2 / F2 = (Gm1m2 / 4) × (16 / Gm1m2)

2/F2 = 16 / 4

Cross multiply

2 × 4 = 16 × F2

8 = 16F2

F2 = 8/16

F2 = 0.5N

7 0
3 years ago
How can a person detect infrared rays without an instrument?
natita [175]
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zysi [14]

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4 years ago
If a large housefly 2.4 m away from you makes a noise of 47.0 dB, what is the noise level (in dB) of 5400 flies at that distance
dem82 [27]

Answer:

the noise level of 5400 flies is equal to 84.32 dB

Explanation:

Noise made by house flies = 47 dB from the distance of 2.4 m

to calculate the noise of 5400 flies at a distance of 2.4 m.

the intensity of noise

  10 log_{10}(\dfrac{I}{I_0}) = 47 dB

now,  I' = 5400 I₀

=     10 log_{10}(\dfrac{5400 I}{I_0})

=    10 [log_{10}[5400] +log_{10}(\dfrac{I}{I_0}))      

= 10 ( 3.732 + 4.7 )                            

= 84.32 dB                                          

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