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4 years ago

Why does the Earth system include

1 answer:

3 0

If you meant "What does the Earths system include?" here's your answer. The Earths system includes the atmosphere, which has all the planets air in it.

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Which component measures the potential difference across a branch in a circuit? A.switch. B.resistor. C.ammeter. D.voltmeter.

Mademuasel [1]

Answer: The correct answer is option (D).

Explanation:

Voltmeter is a device which measures the the voltage applied across the circuit. It is an electrical instrument used to measure the electric potential between the two points in an electric circuit.

Where as:

A switch is the device which used to connect or disconnect the circuit.

Resistor is a device which opposes the flow of current is an electric circuit.

An ammeter the is an electrical device which measures the amount of current in flowing in amperes in an electrical circuit

Hence,the correct answer is option (D).

4 0

3 years ago

Read 2 more answers

How does the motion of the molecules change when you increase the temperature

borishaifa [10]

Answer:

They speed up as temperature increases.

Explanation:

As temperatures increases within a molecule the particles will speed up.

6 0

3 years ago

A 11.3-kg object oscillates at the end of a vertical spring that has a spring constant of 2.20 ✕ 104 N/m. The effect of air resi

3241004551 [841]

Answer:

(a) the frequency of the dampened oscillation is 7.02 Hz

(b) percentage decrease in amplitude of the oscillation in each cycle is 2%

Explanation:

Given;

mass of the object = 11.3 kg

the spring constant = 2.2 X 10⁴ N/m.

damping coefficient b = 3.00 N · s/m

Part (a) the frequency of the dampened oscillation

The oscillation frequency is calculated as follows;

$\omega _D = \sqrt{\omega_o^2 -(\frac{b}{2m})^2}\\\\\omega_o^2 = \frac{k}{m} =\frac{2.2X10^{4}}{11.3} = 1946.903rad/s\\\\thus, \omega _D = \sqrt{1946.903-(\frac{3}{2*11.3})^2} =44.12 rad/s$

The damped frequency $= \frac{\omega _D}{2\pi } = \frac{44.12}{2\pi } = 7.02 Hz$

Part (b) percentage decrease in amplitude of the oscillation in each cycle

The amplitude of the oscillation depends on the damping coefficient (b) and period (T), and it is given as;

$A(t) = e^{-\frac{b}{2m}(t)}$

After one cycle, the amplitude changes from A(t) to A(t+T), where T is the period of the oscillation.

$A(t +T) = e^{-\frac{b}{2m}(t+T)}$

Percentage decrease in amplitude is gotten by dividing A(t) by A(t+T)

$= \frac{e^{-\frac{b}{2m}(t)}}{e^{-\frac{b}{2m}(t+T)}} =e^{-\frac{b}{2m}(T)}$

But T = 1/f

Substituting the values of the parameters in the above equation, we will have;

$=e^{-\frac{b}{2m}(T)} = e^{-\frac{3}{2X11.3}(\frac{1}{7.02})} = 0.98$

Percentage decrease = 1 - 0.98 = 0.02 = 2%

4 0

4 years ago

circular saw blade of diameter 0.190 m starts from rest. In a time interval of 5.80 s it accelerates with constant angular accel

marta [7]

Answer:

Explanation:

We shall apply newton's law equation valid for rotational motion .

ωt = ω₀ + α t where ωt is angular velocity after time t , ω₀ is angular velocity at t= 0 and α is angular acceleration

145 = 0 + α x 5.8

α = 25 rad / s²

B )

θ = ω₀ t + 1/2 α t²

= 0 + .5 x 25 x 5.8 x 5.8

= 420.5 rad .

4 0

3 years ago

Which direction (toward the sun/away from the sun) is the North Pole pointing when it is summer for the Southern Hemisphere?

adoni [48]

The Seasons. When the North Pole tilts most toward the sun, the Northern Hemisphere experiences summer. This occurs when the Earth is farthest away from the sun, and begins around June 21-22. ... This brings about winter in the Southern Hemisphere, called the Winter Solstice.

5 0

3 years ago