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SpyIntel [72]
3 years ago
15

Davis notcies that his hair is decreasing exponentially at a rate of 10% per year. If he starts with 100,000 hairs on his head,

how many hairs will he have after 3 years? Remaining amount= 100,000(1-0.1)^3
Mathematics
1 answer:
beks73 [17]3 years ago
8 0
100,000×(1−0.1)^(3)
=72,900
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Select the statement that best justifies the conclusion based on the given information. l is in plane M, x is on line l Conclusi
egoroff_w [7]

Answer:

If a plane contains a line, it contains the points on the line

Step-by-step explanation:

I got it right on a quiz

8 0
3 years ago
Can you please show me how you got the answer (50 points)
AlexFokin [52]

<em>Answer:</em>

<em />4x^{6}2y^{-2}<em />

<em>Step-by-step explanation:</em>

<em>We can use a property I like to call SEi-F. (Subtract Exponents in a Fraction)</em>

<em>But first, there is an exponent outside of the parentheses in both places. We can use the Power of Parentheses to simplify and then use the SEi-F.</em>

<em>We will start with the x in the numerator.</em>

<em>3*4 = 12</em>

<em>Now for the y in the numerator.</em>

<em>4*4 = 16</em>

<em>Our new numerator is </em>4(2x^{12}y^{16})<em />

<em>We do need to simplify the numerator one more time to get rid of the 4 outside the parentheses.</em>

<em>We will start with x's coefficient.</em>

<em>2*4 = 8</em>

<em>Now for y's coefficient.</em>

<em>1**4 = 4</em>

<em>*y seems to have no coefficient, but if so, it has a coefficient of 1. This applies to other variables.</em>

<em>Our final simplified numerator is </em>8x^{12}4y^{16}<em>.</em>

<em>Repeat with the denominator.</em>

<em>Try it yourself!</em>

<em>Make sure that when you finish, you finish the fraction.</em>

<em>After completing the denominator, your completed fraction should be:</em>

<em />\frac{8x^{12}4y^{16}}{4x^{6}2y^{18}}<em />

<em>Now we can use the SEi-F to complete the problem.</em>

<em>Start with x.</em>

<em>8x - 4x = 4x</em>

<em>12 - 6 = 6</em>

<em>The first term is </em>4x^{6}<em>.</em>

<em>Now for y.</em>

<em>4y - 2y = 2y</em>

<em>16 - 18 = -2</em>

<em>The second term is </em>2y^{-2}<em />

<em>The complete, simplified equation is </em>4x^{6}2y^{-2}<em>.</em>

<em>I could be wrong on the answer, but the work should be correct.</em>

<em>Hope this helps. Have a nice day. Oh, and one more thing. Surprised I'm not stealing points?</em>

7 0
3 years ago
When f(x)=-3, what is x?
Anna35 [415]

Answer:

Step-by-step explanation:

For example, if f(x)   =  2x   + 7

      then         f(-3) = 2(-3) + 7

                     f(-3) = 1

3 0
3 years ago
The following is an incomplete paragraph proving that the opposite sides of parallelogram ABCD are congruent:
Setler [38]

Answer:

The sentence which accurately completes the proof is: "Triangles BCA and DAC are congruent according to the Angle-Side-Angle (ASA) Theorem." ⇒ 2nd answer

Step-by-step explanation:

Let us revise the cases of congruence

  • SSS ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ
  • SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and including angle in the 2nd Δ
  • ASA ⇒ 2 angles and the side whose joining them in the 1st Δ ≅ 2 angles and the side whose joining them in the 2nd Δ
  • AAS ⇒ 2 angles and one side in the 1st Δ ≅ 2 angles and one side in the 2nd Δ
  • HL ⇒ hypotenuse leg of the 1st right Δ ≅ hypotenuse leg of the 2nd right Δ  

In Parallelogram ABCD

∵ Segment AB is parallel to segment DC

∵ Segment BC is parallel to segment AD

- Construct diagonal A C with a straightedge

In Δs BCA and DAC

∵ AC is congruent to itself ⇒ Reflexive Property of Equality

∵ ∠BAC and ∠DCA are congruent ⇒ Alternate Interior Angles

∵ ∠BCA and ∠DAC are congruent ⇒ Alternate Interior Angles

- AC is joining the congruent angles

∴ Δ BCA is congruent to Δ DAC by ASA Theorem of congruence

By CPCTC

∴ AB is congruent to CD

∴ BC is congruent to DA

The sentence which accurately completes the proof is: "Triangles BCA and DAC are congruent according to the Angle-Side-Angle (ASA) Theorem."

3 0
3 years ago
Dilate line f by a scale factor of 2 with the center of dilation at the origin to create line f'. Where are points A' and B' loc
miss Akunina [59]

Answer:

Option (1).

Step-by-step explanation:

Given question is incomplete: find the complete question in the attachment.

From the given figure, coordinates of the points A and B are (0, 2) and (2, 0) respectively.

Slope of line AB = \frac{(y_{2}-y_{1})}{(x_{2}-x_{1})}

                      m_{1}=\frac{2-0}{0-2}=-1

When these points are dilated by a scale factor = 2, about the origin

Rule for the dilation → (x, y) → (kx, ky)

Where k = scale factor

Coordinates of the points A' and B' will be (0, 4) and (4, 0)

Slope of the line A'B' = \frac{(y_{2}-y_{1})}{(x_{2}-x_{1})}

                             m_{2}=\frac{4-0}{0-4}=-1

Since m_{1}=m_{2} , both the lines AB and A'B' will be parallel.

Therefore, option (1) will be the answer.

4 0
3 years ago
Read 2 more answers
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