Answer:
Option A.
Step-by-step explanation:
The given question is incomplete. Here is the complete question.
P(n) models the price (in dollars) of a pack of n bulbs at a certain store.
When does the price of a pack increase faster ?
n 4 10 12
P(n) 12 25 28
When does the price of a pack increase faster ?
A. Between 4 and 10 bulbs
B. Between 10 and 12 bulbs
C. The price increases at the same rat over both the intervals.
To solve this question we will find the rate of increase in the prices per pack in the given intervals.
From n = 4 to n = 10
Rate of increase in price = 
= 
= 2.166 ≈ $2.17 per pack
From n = 10 to n = 12
Rate of increase in price = 
=
= $1.5 per pack
Therefore, price per pack increases faster between n = 4 and n = 10 as compared to n = 10 to n = 12.
Option A is the answer.
Answer:
4500cm^3
Step-by-step explanation:
We use the normal formula for volume V= L•W•H just changing the H value from 20 to 10 because the water isn't at the full hight
10•30•15=4500
hope this helps <3
You can use any data set in this table (except the row with x) to get the ratio.
so 20/196 is the ratio which equals about .102041
then multiply that decimal by the weight in the x row to see what x is
so 1078(.102041) = 110.000198 just round that to 110. you can also verify that ratio by checking other data points. for instance
490(.102041) = 50.00009 or 50
so you know x is 50 so answer is either b or d
then you know the ratio .102041, so does (10/98) = .102041
or does (98/10) = .102041
if you do the division you will see that (10/98) = .102041
so the answer is D
<em>#</em><em>CARRYONLEARNING</em><em> </em>
<em>.</em><em>.</em><em>LOVEUALL</em><em>.</em><em>.</em><em>.</em>
You’re full of cap don’t cap next time you’re capping the answer is 5/3