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ollegr [7]
3 years ago
8

Alysia learns that when she opens a new bag of candy, she has a 2/5 chance of pulling out a piece of ridiculous raspberry and a

1/3 chance of pulling got a piece of killer kiwi. Could she have a 4/15 chance of pulling out a piece of Perfect Pitch? explain your reasoning.
Mathematics
2 answers:
Viktor [21]3 years ago
8 0
Yes, 2/5 has a denominator of 5, 1/3 having a denominator of 3, and 4/15 has a denominator of 15. 3 and 5 are factors of 15, so 3 times 5 = 15, 5 times 3 = 15 15 times 1 = 15. What you do the denominator, you must do to the numerator, so 1 times 5 = 5(final fraction is 5/15), 2 times 3 = 6(final fraction is 6/15) and the 4/15 stays the same. 5 + 6 + 4 = 15, final answer is 15/15, that's the entire bag, and she could have a 4/15 chance of pulling out a Perfect Pitch.
Arlecino [84]3 years ago
7 0
2/5=6/15
1/3=5/15
       11/15

yes. that would be the last one possible.
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How many garbage cans should be placed in each campground? Explain how you can use addition or multiplication to find the answer
Vikentia [17]

Answer:

Step-by-step explanation:

Multiplication

Ratio of Tables to garbage = 8:3

Small camp ground:

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\frac{8}{3}=\frac{40}{x}\\\\\frac{8*5}{3*5}=\frac{40}{x}\\\\\frac{40}{15}=\frac{40}{x}\\\\

x = 15

Small campground with 40 picnic table needs 15 garbage cans

Large picnic ground:

120 picnic tables and let y be the number of garbage cans

\frac{8}{3}=\frac{120}{y}\\\\\frac{8*15}{3*15}=\frac{120}{y}\\\\\frac{120}{45}=\frac{120}{y}

y= 45

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3 0
2 years ago
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Tanzania [10]
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6 0
3 years ago
2v^2-12 =-12v <br> Would really appreciate it loves❤️
Black_prince [1.1K]

For this case we have the following equation:

2v ^ 2-12 = -12v

Rewriting we have:

2v ^ 2 + 12v-12 = 0

Dividing by 2 to both sides of the equation:

v ^ 2 + 6v-6 = 0

We apply the quadratic formula:

x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}

We have to:

a = 1\\b = 6\\c = -6

Substituting:

x = \frac {-6 \pm \sqrt {6 ^ 2-4 (1) (- 6)}} {2 (1)}\\x = \frac {-6 \pm \sqrt {36 + 24}} {2}\\x = \frac {-6 \pm \sqrt {60}} {2}\\x = \frac {-6 \pm \sqrt {4 * 15}} {2}\\x = \frac {-6 \pm2 \sqrt {15}} {2}

Thus, we have two roots:

x_ {1} = - 3+ \sqrt {15}\\x_ {2} = - 3- \sqrt {15}

ANswer:

x_ {1} = - 3+ \sqrt {15}\\x_ {2} = - 3- \sqrt {15}

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Answer:25

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3 years ago
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