A chocolate shop sells chocolates with a variety of different fillings.

Mathematics

1 answer:

alexandr402 [8]3 years ago

7 0

Answer:

There is a $\frac{2}{21}$ chance of picking caramel-filled chocolate.

Step-by-step explanation:

To set this up, you need to make it a fraction. The denominator of the fraction is how many total chocolates you can pick from. You can figure this out by adding all of the chocolate choices together:

68 hazelnut + 8 caramel + 8 orange = 84 chocolates.

The numerator is defined by the number of caramel chocolates, in this case it is 8. That means the fraction will look like:

$\frac{8}{84}$

Now that can be simplified down. I divided the top and bottom both by 4 to get $\frac{2}{21}$ and that is as far down as it can go. Therefore that is the probability you will get a caramel-filled chocolate.

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3 years ago

(a) Suppose you have 9 gold coins that look identical, but you also know one (and only one) of them is counterfeit. The counterf

alisha [4.7K]

Answer:

Step-by-step explanation:

You can split the coins into 3 groups, each of them has 3 coins. Weigh group 1 vs group 2, if one is lighter, that group has the fake coin. If both groups weigh the same, then group 3 has the fake coin.

Continue to split the group that has the fake coin into 3 groups, each group has 1 coin. Now apply the same procedure and we can identify the fake coin.

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b) if you have $3^n$ coins then you can apply the same approach and find the fake coin with just n steps. By splitting up to 3 groups each step, after each step you should be able to narrow down your suspected coin by 3 times.