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The area of figure ABCDEF can be computed as the sum of the areas of trapezoid ACDF and triangle ABC, less the area of trangle DEF.
trapezoid ACDF area = (1/2)(AC +DF)·(CD) = (1/2)(8+5)(6) = 39
triangle ABC area = (1/2)(AC)(2) = 8
triangle DEF area = (1/2)(DF)(2) = 5
Area of ABCDEF = (ACDF area) + (ABC area) - (DEF area) = 39 +8 -5 = 42
The actual area of ABCDEF is 42 square units.
trapezoid ACDF area = (1/2)(AC +DF)·(CD) = (1/2)(8+5)(6) = 39
triangle ABC area = (1/2)(AC)(2) = 8
triangle DEF area = (1/2)(DF)(2) = 5
Area of ABCDEF = (ACDF area) + (ABC area) - (DEF area) = 39 +8 -5 = 42
The actual area of ABCDEF is 42 square units.
The values of x and y are 15 and 7 respectively
The angles formed from the intersection of two lines at X are equal and vertically opposite angles.
From the figure shown, we can conclude that:
2(5x-5) = 6x + 50 (vertically opposite angle)
Expand
10x - 10 = 6x + 50
10x - 6x = 50 + 10
4x = 60
x = 60/4
x =15
Similarly;
5y + 5 = 7y - 9
Collect the like terms;
5y - 7y = -9 - 5
-2y = -14
y = 14/2
y = 7
Hence the values of x and y are 15 and 7 respectively
Learn more here: brainly.com/question/15198257
