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lara31 [8.8K]
3 years ago
12

What is the product in lowest terms?

Mathematics
2 answers:
grin007 [14]3 years ago
6 0
#1. D. \frac{9}{14}* \frac{-7}{12} = \frac{-63}{168}= \frac{-3}{8}

#2. A. <u />\frac{1}{3} of  \frac{3}{4}=0.25= \frac{1}{4}
brilliants [131]3 years ago
3 0
C 
because you would take 3/4 and multiply it by 3/3 to get the denominator to 12
and you would multiply 1/3 by 4/4 again to get the denominator to 12.
You are getting the denominator to 12 because 12 is 3 and 4s Most Common multiple!
Now that you have multiplied them you should have 9/12 and 4/12 
Then you subtract 4 from 9 to get 5.
So the answer is 5/12!

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Last questions, plz help
Goryan [66]

Answer:

9. a_n=7+6n

10. a_n=a_{n-1}+7

Step-by-step explanation:

9. Given the sequence

13, 19, 25, ...

In this sequence,

a_1=13\\ \\a_2=19\\ \\a_3=25\\ \\...

Note that

a_2-a_1=19-13=6\\ \\a_3-a_2=25-19=6,

then the common difference in this sequence is d=6

You have

a_1=13\\ \\d=6,

then the explicit formula is

a_n=a_1+(n-1)d\\ \\a_n=13+(n-1)\cdot 6\\ \\a_n=13+6n-6\\ \\a_n=7+6n

10. Given the sequence

-10,-3, 4, 11, ...

In this sequence,

a_1=-10\\ \\a_2=-3\\ \\a_3=4\\ \\a_4=11\\ \\...

Note that

a_2-a_1=-10-(-3)=-10+3=-7\\ \\a_3-a_2=-3-4=-7\\ \\a_4-a_3=11-4=7,

then the common difference in this sequence is d=7

You have

a_1=-10\\ \\d=7,

then the recursive formula is

a_n=a_{n-1}+d\\ \\a_n=a_{n-1}+7

5 0
3 years ago
If 2tanA=3tanB,then prove that tan(A-B)=sin2B/(5-cos2B) ...?
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tan A = 3 tan B/2
tan ( A - B ) = ((3 tan B/ 2)-tan B) / ( 1 + 3 tan² B/2)=
= (tan B/2)  / ( 2 + 3 sin²B/cos²B )=
= (sin B / cos B) / (( 2cos² B+3sin²B)/cos²B)=
=( sin B cos B ) / ( 2 cos²B + 3 ( 1 - cos² B ) ) =
= (sin B cos B ) / ( 2 cos² B + 3 - 3 cos² B ) =
= ( sin 2 B ) / 2 ( 3 - cos² B ) =
= ( sin 2 B ) / ( 6 - cos² B )=
= ( sin 2 B ) / ( 5 + 1 - 2 cos² B )=
= ( sin 2 B ) / ( 5 + sin² B + cos ² B - 2 cos² B ) =
= ( sin 2 B ) / ( 5 - ( cos² B - sin² B ) ) =
= ( sin 2 B ) / ( 5 - cos 2 B )  - correct 
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2 years ago
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