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lapo4ka [179]
3 years ago
13

MAKE A QUESTION FOR THIS EQUATION 5n +1.39=8.89 don't have to solve

Mathematics
2 answers:
Paha777 [63]3 years ago
6 0

Answer:

What is the missing number when n = 1.5?

5n+___=8.89

yulyashka [42]3 years ago
6 0
8.89-1.39=n
What is n?
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During a period of 28 minutes, a music station played 8 minutes of commercials. What is the ratio of music they played to commer
USPshnik [31]
So first write down the fraction which is 8/28
then make it into its simplest form which is 2/7
then make it into ration form it is 2:7
reading 2 is to 7
6 0
4 years ago
HELP HURRY -- Tell the kind of symmetry this figure has: point, line, plane. (Select all that apply.)
slava [35]

Answer:

point and line

Step-by-step explanation:

it is not a plane because it doesnt have sides

8 0
3 years ago
After a late night of studying, Ebony decides to grab a latte before class so she can stay awake through her morning lecture. Sh
Rzqust [24]

Answer:

P(Same\ Bill) = \frac{1}{3}

P(Second

P(Both\ Even) = \frac{1}{9}

Pr(One\ Odd) = \frac{4}{9}

P(Sum < 10) = \frac{1}{3}

Step-by-step explanation:

Given

Bills: \$1, \$5, \$10

Selection = 2\ bills

The sample space is as follows:

This implies that we construct possible outcome that Ebony selects a bill, returns the bill and then select another.

This means that there are possibilities that the same bill is selected twice.

So, the sample space is as follows:

S = \{(1,1), (1,5), (1,10), (5,1), (5,5), (5,10), (10,1), (10,5), (10,10)\}

n(S) = 9

Solving (a): P(Same\ Bill)

This means that the first and second bill selected are the same.

The outcome of this are:

Same = \{(1,1),(5,5),(10,10)\}

n(Same\ Bill) = 3

The probability is:

P(Same\ Bill) = \frac{n(Same\ Bill)}{n(S)}

P(Same\ Bill) = \frac{3}{9}

P(Same\ Bill) = \frac{1}{3}

Solving (a): P(Second  < First\ Bill)

This means that the second bill selected is less than the first.

The outcome of this are:

Second < First = \{(1,5), (1,10), (5,10)\}

n(Second < First) = 3

The probability is:

P(Second

P(Second

P(Second

Solving (c): P(Both\ Even)

This means that the first and the second bill are even

The outcome of this are:

Both\ Even = \{(10,10)\}

n(Both\ Even) = 1

The probability is:

P(Both\ Even) = \frac{n(Both\ Even)}{n(S)}

P(Both\ Even) = \frac{1}{9}

Solving (e): P(Sum < 10)

This question has missing details.

The correct question is to determine the probability that, the sum of both bills is less than 10

The outcome of this are:

One\ Odd = \{(1,10), (5,10), (10,1), (10,5)\}

n(One\ Odd) = 4

The probability is:

Pr(One\ Odd) = \frac{n(One\ Odd)}{n(S)}

Pr(One\ Odd) = \frac{4}{9}

 

Solving (d): P(One\ Odd)

This question has missing details.

The correct question is to determine the probability that, exactly one of the bills is 0dd

The outcome of this are:

Sum < 10 = \{(1,1), (1,5), (5,1)\}

n(Sum < 10) = 3

The probability is:

P(Sum < 10) = \frac{n(Sum < 10)}{n(S)}

P(Sum < 10) = \frac{3}{9}

P(Sum < 10) = \frac{1}{3}

 

3 0
3 years ago
I need help! This is really hard for me
Goryan [66]
Total clay = πr²h = π x (4÷2)² x 6 = 12π in³

Clay ball = 4/3 x π x (1)³ = 4/3 π in³

Number of clay balls that can be made = 12π ÷ 4/3 π = 9

--------------------------------------------------
Answer: 9 clay balls.
--------------------------------------------------

8 0
3 years ago
3 1⁄8 − 1 7⁄8 =<br> what is the answer
Usimov [2.4K]

2 6/8 i think hope this helps

5 0
3 years ago
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