10x^2 = 50x.....subtract 50x from both sides
10x^2 - 50x = 0...factor
10x(x - 5) = 0
10x = 0
x = 0 <== this one is eliminated because x cannot be zero
x - 5 = 0
x = 5 <== ur answer
All that you are doing is trying to fiigure out the Frequency of all the tally marks!!
Answer:Pois(ln(200))
Step-byy-step explanation:
Let N be the number of received calls in a day
That is
N∼Pois(λ).
0.5% = 0.5/100 = 1/200 of no calls
P(N=0)=e^−λ=1/200
-λ=e^(1/200)
λ=in(200)
Our number of calls in a day is distributed Pois(ln(200)).
Answer:
-1/6
Step-by-step explanation:
= 1/3 (-1-1) x -1/4 (-1)
= 1/3 (-2) x 1/4
= -2/3 x 1/4
= -2\12
2 and 12 can cancel out each other.
so the answer will be.
= -1/6.