What it is basically asking is if Y = -4, find the value of x in the equation 6x + 7y = 4x + 4y
To solve this you just need to plug in -4 for y and solve for x
6x + 7(-4) = 4x + 4(-4)
6x - 28 = 4x - 16
Now isolate x by adding 28 to both sides
6x - 28 + 28 = 4x - 16 + 28
6x = 4x + 8
and subtract 4x from both sides
6x - 4x = 4x - 4x + 8
2x = 8
divide both sides by 2
2/2x = 8/2
x = 4
x = 4, y = -2
Answer: (4, - 2)
Hope it helps :)
Bransliest would be appreciated
(2x³ - 5x² + 8)(x + 3) = ?
First step is to distribute.
2x^4 + 6x³ - 5x³ - 15x² + 8x + 24
Now combine like terms.
2x^4 + x³ - 15x² + 8x + 24
This is your answer, since you can't simplify any further or solve it without some more information.
Answer:
x=2
y=3
Solution:
First we find common denominators. It is "xy". Then we multiply numerators by common denominator. We get followings:
(4y-3x)/xy=1; (6y+15x)/xy=8
Then
4y-3x=xy;
6y+15=8xy
Multiply first equasion by 5
20y-15x=5xy
Now we add two equasions to get one
20y-15x=5xy
6y+15x=8xy
We get
26y=13xy
Cut "y" and we will find "x"
26=13x
x=2
Put x value into the first equasion(4y-3x=xy) to find out "y"
4y-6=2y
2y=6
y=3
The coordinate plane is missing, so i have attached it.
Answer:
Perimeter of room = 140 ft
Area of room = 1200 sq.ft
Step-by-step explanation:
From the cordinate plane attached, we can see the polygon QRST which represents the floor plan of the roo.
Thus;
The length of the sides of the room are;
ST = RQ = 30
QT = RS = 40
Perimeter of a rectangle is the sum of all sides of the rectangle.
Thus, perimeter of the room = (30 × 2) + (40 × 2) = 140 ft
Now, area of a rectangle is the product of two perpendicular sides.
Thus area of room = 40 x 30 = 1200 sq.ft
The answer is 58 I think 166-8= 158
