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2 years ago

How to do: -8(1-a)=-7-(1-3a)

Mathematics

1 answer:

Fiesta28 [93]2 years ago

7 0

In this question, you're solving for a.

Solve for a:

-8(1 - a) =-7 -(1 - 3a)

use the distributive property

-8 + 8a = -7 -(1 - 3a)

-8 + 8a = -7 - 1 + 3a

combine like terms

-8 + 8a = -8 + 3a

subtract 3a from both sides

-8 + 5a = -8

add 8 to both sides

5a = 0

divide both sides by 5

a = 0

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If a₁ = 4 and an = 5an-1 then find the value of a5.

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The value of $a_{5}$ is 2500, when $a_{1}=4$ and $5a_{n-1}$ .

Given that, $a_{1}=4$ and $5a_{n-1}$ .

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An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant.

Now, to find the value of $a_{5}$ :

$a_{2} =5a_{2-1}=5a_{1}=5 \times4=20$

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