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2 years ago

Which property is demonstrated below?

Mathematics

2 answers:

rewona [7]2 years ago

6 0

Answer:

The associative property allows us to change groupings of addition or multiplication and keep the same value. (a+b)+c = a+(b+c) and (ab)c = a(bc).

Juli2301 [7.4K]2 years ago

4 0

There’s no picture soooooo

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Find the perimeter of ABC with vertices A (1,-6), B (1,-3),<br> and C (-4,-6).

Crazy boy [7]

Answer:

$p = 8 + \sqrt{34} = 13.83095...$

Step-by-step explanation:

we can easily calculate the perimeter of three points, using vectors. See the picture...

5 0

2 years ago

Is a percent a number?

mars1129 [50]

Yes, percent is a number.

7 0

2 years ago

Read 2 more answers

Decrease 1440 by 80%

mario62 [17]

Answer:

288 will be ur ans

Step-by-step explanation:

1440 x 80/100

=1152

1440-1152

=288

5 0

3 years ago

Which expression is equivalent??? help!

dexar [7]

Answer:

The equivalent expression for the given expression $\sqrt[3]{256x^{10}y^{7} }$ is

$4x^{3} y^{2}(\sqrt[3]{4xy} )$

Step-by-step explanation:

Given:

$\sqrt[3]{256x^{10}y^{7} }$

Solution:

We will see first what is Cube rooting.

$\sqrt[3]{x^{3}} = x$

Law of Indices

$(x^{a})^{b}=x^{a\times b}\\and\\x^{a}x^{b} = x^{a+b}$

Now, applying above property we get

$\sqrt[3]{256x^{10}y^{7} }=\sqrt[3]{(4^{3}\times 4\times (x^{3})^{3}\times x\times (y^{2})^{3}\times y )} \\\\\textrm{Cube Rooting we get}\\\sqrt[3]{256x^{10}y^{7} }= 4\times x^{3}\times y^{2}(\sqrt[3]{4xy}) \\\\\sqrt[3]{256x^{10}y^{7} }= 4x^{3}y^{2}(\sqrt[3]{4xy})$

∴ The equivalent expression for the given expression $\sqrt[3]{256x^{10}y^{7} }$ is

$4x^{3} y^{2}(\sqrt[3]{4xy} )$

5 0

3 years ago

X+6=x<br> can you help please thank you

Anna35 [415]

x + 6 = x

there is literally no solution.

7 0

2 years ago