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Sliva [168]
3 years ago
11

Which property is demonstrated below?

Mathematics
2 answers:
rewona [7]3 years ago
6 0

Answer:

The associative property allows us to change groupings of addition or multiplication and keep the same value. (a+b)+c = a+(b+c) and (ab)c = a(bc).

Juli2301 [7.4K]3 years ago
4 0
There’s no picture soooooo
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X = y 2 - 1
pochemuha
Your answer would be option B. 2y² - y - 6 = 0. This is because if you were to substitute x = y² - 1 into the equation 2x - y = 4, you would get 2(y² - 1) - y = 4, which expands into 2y² - 2 - y = 4, and then simplifies to 2y² - y - 6 = 0.
I hope this helps!
7 0
3 years ago
Read 2 more answers
Given f(x) = –2x + 2, find f(6).
Alla [95]

Answer:

-10

Step-by-step explanation:

8 0
3 years ago
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Plz help solve this thanks
Burka [1]

Answer:

y= -3/2

Step-by-step explanation:

........................

3 0
3 years ago
3-(6x-5)+2= -5(6x+2)<br><br> Solve for x
WARRIOR [948]

Answer:

x

=

−

v

3

24

−

17

24

Step-by-step explanation:

4 0
3 years ago
Suppose a student carrying a flu virus returns to an isolated college campus of 2000 students. Determine a differential equation
ad-work [718]

Answer:

x(t) = 2000 - e^(-k*t)

Step-by-step explanation:

Interpretation:

No . infected student = x

Total student = 2000

rate of infected students = dx / dt

not-infected student = 200 - x

The general rate at which student are infected can be expressed as below:

dx / dt = k * ( 2000 - x )

To develop an expression of x(t) we integrate the above expression by separating variables:

dx / (2000 - x ) = k * dt

Now integrate:

\int\limits{\frac{1}{(2000-x)} } \, dx = k *  \int\limits{dt}\\\\- ln (2000-x) = k*t + C\\\\

@ t = 0 , infected students x = 0

Hence,

C = - ln (2000)

- ln (2000-x) = k*t + - ln (2000)\\\\ln (\frac{2000-x}{2000}) = -k*t\\\\ 2000 - x = e^(-kt)\\\\x(t) = 2000 - e ^ (-k*t)

6 0
3 years ago
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