The formula can be used to work outthe cost, in riyals, of hiring a helmet inQatar for a number of days.Kasun wants to hire a bi
1 answer:
Answer:
The answer is below
Step-by-step explanation:
a) Cost of hiring the bicycle for 14 days is:
Cost = 65 * 14 days + 44 = 954 riyals
b) The number of days the bicycle is hired is to be the same as the number of days the bicycle is to be hired. Let us assume that the bicycle and helmet is to be hired for x days, hence:
Cost of bicycle = 65 * x + 14 = 65x + 44
Cost of helmet = 12.5 * x = 12.5x
Total cost = 65x + 44 + 12.5x = 77.5x + 44
Since 750 riyals is available, hence:
750 = 77.5x + 44
77.5x = 706
x = 9.11
Therefore the maximum number of days is 11. The total cost for 11 days is:
Total cost = 77.5(9) + 44 = 741.5 riyals
Money not spent = 750 riyals - 741.5 riyals = 8.5 riyals
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Answer:
See below.
Step-by-step explanation:
First, notice that this is a composition of functions. For instance, let's let and
. Then, the given equation is essentially
. Thus, we can use the chain rule.
Recall the chain rule: . So, let's find the derivative of each function:
We can use the Power Rule here:
Now:
Again, use the Power Rule and Sum Rule
Now, we can put them together:
Let's say hmm let's use the figures in thousands, so
model A costs 90 + 4 per year, so... ok.. after "t" years, then the cost for model A is then 90 + 4*t, or A = 90 + 4t.
now, model B is 70 + 10 per year, so,... after "t" years, model B is then
B = 70 + 10 * t, or B = 70 + 10t.
if we were to assume A < B, namely the cost of A is less than B, what would the years be? namely, what's "t"?
after that period, then A becomes cheaper than B.
model A costs 90 + 4 per year, so... ok.. after "t" years, then the cost for model A is then 90 + 4*t, or A = 90 + 4t.
now, model B is 70 + 10 per year, so,... after "t" years, model B is then
B = 70 + 10 * t, or B = 70 + 10t.
if we were to assume A < B, namely the cost of A is less than B, what would the years be? namely, what's "t"?
after that period, then A becomes cheaper than B.