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3 years ago

Three of nine softball players play outfield.what fraction of the players play outfield? Write the answer as a reduced fraction

1 answer:

6 0

Because 3 players play in the outfield and there are 9 players all together, you would write the fraction as 3/9. To reduce, you would get 1/3. (Dividing numerator and denominator by 3 because it is a common denominator).

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I am giving away 10 points to anybody who provides correct answers with explanations.

QveST [7]

Answer:

$5)\ f(n) = 4v$

$6)\ \frac{1}{4}n$

$7)\ True$

This might not be correct though. I'm only in middle school lol. I am sure about the last one.

6 0

2 years ago

Solve the inequality for x. 75+15x is greater than or equal to 140

Gre4nikov [31]

75+ 15x ≥ 140
⇒ 15x ≥ 140 -75
⇒ 15x ≥ 65
⇒ x ≥ 65/15
⇒ x ≥ 13/3
⇒ x ≥ 4 1/3

The final answer is x ≥ 4 1/3~

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3 years ago

HELP PLEASEEEE!!!!! <br> find y-intercept on the graph

Gekata [30.6K]

Answer:

-4

Step-by-step explanation:

When looking at the graph look at the y axis and look to see where the line passes through

8 0

3 years ago

Read 2 more answers

Explain how to get that answer!!

ra1l [238]

We need to simplify $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$

First lets factor $\sqrt{14x^3}$

$\sqrt{14x^3}$ = $\sqrt{14} \sqrt{x^3}$
$\sqrt{14} = \sqrt{2} \sqrt{7}$ by applying the radical rule $\sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}$
$\sqrt{x^3} = x^{3/2}$ By applying the radical rule $\sqrt[n]{x^m} = x^{m/n}$

So
$\sqrt{14x^3}$ = $\sqrt{14} \sqrt{x^3}$ = $\sqrt{2} \sqrt{7}x^{3/2}$

Now let's factor $\sqrt{18x}$
By applying the radical rule $\sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}$ ,
$\sqrt{18x} = \sqrt{18} \sqrt{x}$
$\sqrt{18} = \sqrt{2} * 3$

So $\sqrt{18x}$ = $\sqrt{2}*3 \sqrt{x}$

So $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$ = $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3 \sqrt{x} }$

We know that $\sqrt[n]{x} = x^{1/n}$ so $\sqrt{x} = x^{1/2}$

We now have $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3 \sqrt{x}} = \frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3x^{1/2}}$

We know that $\frac{x^a}{x^b} = x^{a-b}$
So $\frac{x^{3/2}}{x^{1/2}} = x^{3/2 - 1/2} = x$

We now got $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3x^{1/2}} = \frac{ \sqrt{2} \sqrt{7} x }{ \sqrt{2}*3}
$

We can notice that the numerator and the denominator both got √2 in a multiplication, so we can simplify them, and we get:
$\frac{ \sqrt{2} \sqrt{7} x }{ \sqrt{2}*3} = \frac{ \sqrt{7}x }{3}$

All in All, we get $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$ = $\frac{ \sqrt{7}x }{3}$

Hope this helps! :D

6 0

3 years ago

Four girls helped Mr. Day plant a garden. For their help, he gave the girls $24 to share equally.later, mrs. day gave each girl

Ksenya-84 [330]

they all split it and is each going to have 6 dollars each plus the extra 2 for cleaning so 8 dollars each.

Answer - $8 Dollars

5 0

3 years ago