And 50% what is the answer please help no links no links

lions [1.4K]

C) 3/9 because there are a total of nine coins and there are three quarters meaning there is a bout a 1 in 3 chance you’ll pull a quarter out

3 0

4 years ago

Times 9/5 = -27 what is the answer

Andreas93 [3]

<h2>Answer:</h2><h2>1.8-27=-25.2.</h2>

I hope I am right ...

4 0

3 years ago

Read 2 more answers

Jade has 121,024 beads. 1/5 of them are glass beads, 1/10 of them are pony beads, and the rest of them are marbled beads. It tak

WARRIOR [948]

Jade can make 403 necklaces.

1/5 of 121024 = 1/5(121024) = 0.2(121024) = 24204.8 = 24204 glass beads
1/10 of 121024 = 1/10(121024) = 0.1(121024) = 12102.4 = 12102 pony beads

To find the number of marbled beads, we add the fraction of the other two kinds together:
1/5 + 1/10

We will use 10 as the denominator:
2/10 + 1/10 = 3/10

The fraction that the marbled beads represents will make up 100%, or the whole number 1:
1-3/10 = 7/10

7/10 of 121024 = 7/10(121024) = 0.7(121024) = 84716.8 = 84716 marbled beads

Since it takes 20 glass beads to make a necklace, we divide the number of glass beads, 24204, by 20:
24204/20 = 1210 necklaces

It takes 30 pony beads to make a necklace. We divide the number of pony beads, 12102, by 30:
12102/30 = 403 necklaces

It takes 50 marbled beads to make a necklace. We divide the number of marbled beads, 84716, by 50:
84716/50 = 1694 necklaces

We must go with the smallest number, in order to ensure we have enough beads; this means she can make 403 necklaces.

3 0

3 years ago

Use the trapezoid rule to estimate the area under the graph of y = x2 + 2 for values of x from 0 to 3.

dimulka [17.4K]

So basically you form little trapaziods to fin =d the area. It's been a long time since I took calculus so Imma have to improvise

Area or trapaziod = area of rectangle + area of triangle so you get
2*1+(3-2)*1/2+3*1+(6-3)*1/2+6*1+(11-6)*1/2=15.5

8 0

3 years ago

The mean finish time for a yearly amateur auto race was 186.32 minutes with a standard deviation of 0.305 minute. The winning c

uranmaximum [27]

Complete Question

The mean finish time for a yearly amateur auto race was 186.94 minutes with a standard deviation of 0.305 minute. The winning car, driven by Roger, finished in 185.85 minutes. The previous year's race had a mean finishing time of 110.7 with a standard deviation of 0.115 minute. The winning car that year, driven by Karen, finished in 110.48 minutes.

Find their respective z-scores.

Who had the more convincing victory?

A. Roger had a more convincing victory because of a higher z-score.

B. Karen a more convincing victory because of a higher z-score.

C. Roger had a more convincing victory, because of a lower z-score.

D. Karen a more convincing victory because of a lower z-score.

Answer:

The correct option is D

Step-by-step explanation:

From the question we are told that

The mean of the current year is $\mu_c = 186.32 \ minutes$