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lora16 [44]
2 years ago
9

Como realizo la factorizacion de estos ejercicios y que caso pertenece a cada uno.... Por favor ayudenme ya que no soy muy buena

con factorizacion... Gracias 1) 6x + 4 2) 6y2 - 4y 3) 10xy + 5xz 4) 3x2y - 9x3y3 5) 8a3bc - 12ab3cd + 4b4c2d2 6) 6z2t3 + 3zst4 - 12z2t3 7) z2 - 49 8) x2 + 3x - 4 9) p2 + 4p + 3 10) s2 - 6s + 8 11) 16x2 - 9 12) x2 + 2x - 24 13) z2 + 6z + 8 14) 4t2 - 9s2 15) x2 + 6x + 9 16) y2 - 15y + 50 17) 5x2 + 25x + 30 18) 2x2 + 7x - 15 19) 3x2 - 3 20) 4y2 - 8y + 3
Mathematics
1 answer:
Goryan [66]2 years ago
8 0
Girl u ain’t getting no answer
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If Chelsea made twice the amount of soup then she made 64. When converted into cups to gallons it will be 4 gallons.
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2 years ago
Answer to : <br> Factorise this <br> 6x squared -5x - 125
IrinaK [193]
Hello!!

= 6x^2 - 5x - 125

= x (6x - 5) - 125

= (6x + 25) (x - 5)

Good luck :)
8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B45%5D%7B55%3F%7D%20" id="TexFormula1" title=" \sqrt[45]{55?} " alt=" \sqrt[45]{55
m_a_m_a [10]

Answer:

6π cm³

Step-by-step explanation:

V = Ah ( A is the base area and h the height ), then

3πh = 18π ( divide both sides by 3π )

h =  = 6

Then the height of the smaller cylinder = 6 - 3 = 3 cm

V = 3π × 3 = 9π cm³ ← volume of smaller can

Step-by-step explanation:

7 0
2 years ago
The identification code on a bank card consists of 1 digit followed by 2 letters. The code must meet the following conditions: T
jasenka [17]

Answer:

For the code we have 3 selections.

The first selection is a digit that must be odd, so the options are {1, 3, 5, 7 ,9}

So we have 5 options.

The second selection is a letter from the set of all the letters (27) minus the set of the vowels (5)

So here we have 27 - 5 = 22 options

The third selection is also a letter from the previous set, but because each letter can be used only one time, and in the previous selection we already selected one of the letters, in this selection we have a letter less than in the previous selection.

Here we have 22 - 1 = 21 options.

The total number of combinations (of possible codes) is equal to the product of the number of options for each selection:

C = 5*22*21 = 2310.

There are 2310 different possible codes

8 0
3 years ago
Please solve this....
ivann1987 [24]

Answer:

the value will be equal to 0

Step-by-step explanation:

see the attached picture for solution --

5 0
3 years ago
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