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lora16 [44]
3 years ago
9

Como realizo la factorizacion de estos ejercicios y que caso pertenece a cada uno.... Por favor ayudenme ya que no soy muy buena

con factorizacion... Gracias 1) 6x + 4 2) 6y2 - 4y 3) 10xy + 5xz 4) 3x2y - 9x3y3 5) 8a3bc - 12ab3cd + 4b4c2d2 6) 6z2t3 + 3zst4 - 12z2t3 7) z2 - 49 8) x2 + 3x - 4 9) p2 + 4p + 3 10) s2 - 6s + 8 11) 16x2 - 9 12) x2 + 2x - 24 13) z2 + 6z + 8 14) 4t2 - 9s2 15) x2 + 6x + 9 16) y2 - 15y + 50 17) 5x2 + 25x + 30 18) 2x2 + 7x - 15 19) 3x2 - 3 20) 4y2 - 8y + 3
Mathematics
1 answer:
Goryan [66]3 years ago
8 0
Girl u ain’t getting no answer
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Can I get some help please?
mamaluj [8]

Answer:

1)   68

    / \

 4     17

  /\

2  2

68=2*2*17

2)  104

   /      \

 4      26

  /\       /\

2  2   2   13

104=2*2*2*13

3) 78

    /\

 2    39

        /\

      3   13

78=2*3*13

4) 225

    /\

  9   25

  /\    /\

 3 3  5 5

225=3*3*5*5

Second Part:

1)  45

    /\

  3  15

       /\

      3 5

45=3*3*5

2)  70

     /\

   2   35

          /\

        5  7

70=2*5*7

3)  54

     /\

   9   6

   /\    /\

  3 3  2 3

54=3*3*2*3

4)  126

      /\

    3   42

          /\

         3  14

               /\

              7  2

126=3*3*7*2

3 0
2 years ago
Find the next three terms of the sequence?
forsale [732]

Answer:

The correct answer is D. -2,592, -15,552, -93,312

Step-by-step explanation:

Each of the terms is the previous term multiplied by 6. You can find this by taking any term and dividing it by the one before it. The answer will always be 6.

-72/-12 = 6

-12/-2 = 6

So, in order to find the next 3, we take the last term and multiply it by 6.

-432 * 6 = -2,592

-2,592 * 6 = -15,552

-15,552 * 6 = -93,312

4 0
3 years ago
A set W of strings of symbols is defined recursively by 1. a, b, and c belong to W. 2. If x belongs to W, so does a(x)c. Which o
Vadim26 [7]

Answer:

a. a(b)c  

b. a(a(b)c)c  

d. a(a(a(a)c)c)c          

Step-by-step explanation:

We are given the following in the question:

a,b,c \in W\\\text{If } x \in W \Rightarrow a(x)c \in W

a. a(b)c

It is given b belongs to W.

b \in W\\\Rightarrow a(b)c \in W

b. a(a(b)c)c

a(b)c \in W\\\Rightarrow a(a(b)c)c \in W

c. a(abc)c

a(abc)c does not belong to W because we cannot find x in W such that a(abc)c belongs to W.

d. a(a(a(a)c)c)c

a \in W\\\Rightarrow a(a)c \in W\\\Rightarrow a(a(a)c)c \in W\\\Rightarrow a(a(a(a)c)c)c

e. a(aacc)c

a(aacc)c does not belong to W because we cannot find x in W such that a(aacc)c belongs to W.

8 0
3 years ago
The sample space for a roll of two number cubes is shown in the table.
katen-ka-za [31]
I think its C but I'm not 100% sure
5 0
3 years ago
Read 2 more answers
Write an equation<br> write an solution<br> and do a check step
melomori [17]

what is one easy addition equation?

1 + 1 = 2

how did you get this ?

you add 1 and 1 together and you will get your solution.

7 0
3 years ago
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