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SOVA2 [1]
3 years ago
12

Point B lies between points A and C on AC. Let x

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
5 0

Set up the following equation for this segment:

x is segment AB's length, and 3x is segment BC's length. 20 is segment AC's length.

Combine like terms:

Divide both sides by 4 to get x by itself:

x will equal 5.

Plug this value into the values for both segments:

Segment AB:

Segment AB is 5 inches long.

Segment BC:

Segment BC is 15 inches long.

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What would the equation be ?
Vikentia [17]

Answer:

y = 4/5x-18/5

Step-by-step explanation:

First we find the slope from the given points (-3,-6) (2,-2)

m = (y2-y1)/(x2-x1)

m = (-2 - -6)/(2 - -3)

   (-2+6)/( 2+3)

  4/5

The slope intercept form of an equation is

y = mx +b  where m is the slope and b is the y intercept

y = 4/5 x +b

Substitute a point into the equation to find b

-6= 4/5(-3) +b

-6= -12/5 +b

Add 12/5 to each side

-6 +12/5 = -12/5 +12/5 +b

Get a common denominator

-30/5 + 12/5 = b

-18/5 =b

The equation is

y = 4/5x-18/5

4 0
4 years ago
Each day for 12 consecutive days, Ricardo jogged for 1 2/3 hours at an average rate of 6 1/4 miles per hour. Find the total dist
kirill115 [55]

Answer:

Your answer is 125 miles

Step-by-step explanation:

1 \frac{2}{3} ×6 \frac{1}{4} = 10 \frac{5}{12}

10 \frac{5}{12} × 12 = 125

8 0
3 years ago
A cylindrical barrel with a radius of 12 feet rests on its round side against a wall. A ladder leans against both the barrel and
frosja888 [35]
The answer is 24 cool
5 0
3 years ago
Which of the following graphs represents a line that is parallel to the line y = - 1/3x - 2?
aalyn [17]
If u can’t read cause it is cut off, the top 10 is 10 and the bottom is -10.

7 0
3 years ago
What is the perimeter of the triangle shown on the coordinate plane, to the nearest tenth of a unit?
Karo-lina-s [1.5K]

Let us find the co ordinates of each vertex of the triangle .

Vertex A ( in firs second quadrant) = ( -5 ,3)

vertex B in third quadrant = ( -5, -5)

vertex C in fourth quadrant = ( 4, -2)

let us use distance formula AB^2 = ( -5 - 3)^2 + (-5 - -5 )^2 = 64 + 0

AB= 8

BC^2 = ( -2 - -5 )^2 + ( 4 - - 5)^2 = 9 + 81 = 90

BC = 9.48

AC^2 = ( -2 -3)^2 +( 4- -5)^2 = 25 + 81 = 106

AC= 10.29

Perimeter = sum of length of AB+ BC+ Ac = 8 + 10.29 + 9.48= 22.77

8 0
3 years ago
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