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raketka [301]
3 years ago
5

URGENT HELP PLEASE: Which of the following statements proves ∆DCG~∆FED? Select all that apply. (see photo)

Mathematics
1 answer:
Pani-rosa [81]3 years ago
3 0

Answer: C and D

Step-by-step explanation:

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? A mug can hold 13.46 oz of coffee without overflowing. The radius of the mug is 3 cm. Given that 1 cm3 equals 0.034 oz, what i
Elan Coil [88]

Answer:

14 cm

Step-by-step explanation:

Given:

A mug can hold 13.46 oz of coffee.

The radius of the mug is 3 cm.

Given that 1 cm^{3} equals 0.034 oz.

Question asked:

What is the height of the mug to the nearest centimeter ?

Solution:

Given that 1 cm^{3} equals 0.034 oz.

By unitary method:

0.034 oz = 1 cm^{3}

1 oz = \frac{1}{0.034}

13.46 oz = \frac{1}{0.034}\times13.46 =395.88 \ cm^{3}

A mug can hold 13.46 oz of coffee means volume of cylinder is given which is 395.88 cm^{3}. Now we can find the height of the mug by using volume of cylinder formula:

volume of cylinder = \pi r^{2} h

                   395.88=\frac{22}{7} \times3\times3\times \ h\\395.88=\frac{198 \ h}{7}

By cross multiplication:

                 395.88\times 7 =198\ h\\2771.16= 198\ h

By dividing both side by 198

h = 13.99 cm

Therefore,  height of the mug to the nearest centimeter is 14 cm.

                   

6 0
4 years ago
Read 2 more answers
If A(-5,7), B(-4,-5), C(-1,-6) and D(4,5) are the vertices of a quadrilateral, find the area of the quadrilateral ABCD.
MrMuchimi
After plotting the quadrilateral in a Cartesian plane, you can see that it is not a particular quadrilateral. Hence, you need to divide it into two triangles. Let's take ABC and ADC.

The area of a triangle with vertices known is  given by the matrix
M = \left[\begin{array}{ccc} x_{1}&y_{1}&1\\x_{2}&y_{2}&1\\x_{3}&y_{3}&1\end{array}\right]

Area = 1/2· | det(M) |
        = 1/2· | x₁·y₂ - x₂·y₁ + x₂·y₃ - x₃·y₂ + x₃·y₁ - x₁·y₃ |
        = 1/2· | x₁·(y₂ - y₃) + x₂·(y₃ - y₁) + x₃·(y₁ - y₂) |

Therefore, the area of ABC will be:
A(ABC) = 1/2· | (-5)·(-5 - (-6)) + (-4)·(-6 - 7) + (-1)·(7 - (-5)) |
             = 1/2· | -5·(1) - 4·(-13) - 1·(12) |
             = 1/2 | 35 |
             = 35/2

Similarly, the area of ADC will be:
A(ABC) = 1/2· | (-5)·(5 - (-6)) + (4)·(-6 - 7) + (-1)·(7 - 5) |
             = 1/2· | -5·(11) + 4·(-13) - 1·(2) |
             = 1/2 | -109 |
<span>             = 109/2</span>

The total area of the quadrilateral will be the sum of the areas of the two triangles:

A(ABCD) = A(ABC) + A(ADC) 
               = 35/2 + 109/2
               = 72
8 0
3 years ago
a street light is mounted at the top of a 15 ft-tall pole. A man 6 ft tall walks away from the pole with a speed of 5 ft/s along
Virty [35]
See attached. The trick is to use similar triangles.

8 0
3 years ago
the morning tempature was -7C. By noon the tempature was 8C. how many degrees has the tampature risen
ddd [48]
It has risen 15 degrees .....
7 0
3 years ago
Read 2 more answers
Simplify the expression - 1/2(5/6+1/3)
mel-nik [20]

Answer:

- 7/12

Step-by-step explanation:

- 1/2 ( 5/6 + 1/3 )

- 1/2 ( 5/6 + 2/6)

- 1/2 ( 7/6 )

- 7/12 or - 0.58

8 0
3 years ago
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