Answer:
The work done to pump all of the kerosene from the tank to an outlet is
Step-by-step explanation:
The work is defined by:
(1)
The force here will be the product between the volume and the kerosene weighing, so we have :

This force will be in-lbs.
Where R is the radius (3 feet)
Then using (1), we have:
Here 8-y is a distance at some point of the tank. Now, to get the work done from the base to the top of the tank we will need to take integral from 0 to 8 feet.




Therefore, the work done to pump all of the kerosene from the tank to an outlet is
I hope it helps you!
Answer:
Step-by-step explanation:
Using the area model and standard algorithm, we have:
332 (tenths)
<u> × 21 </u>
332
<u> 664 </u>
<u> 6972 </u> tenths = 697.2
<u />
30 + 3 tenths
1 300 32 332
20 600 64 664
33.2 × 21 =<u> 30 </u> × <u> 1 </u> = <u> 30 </u>
Ok let’s solve it
5(x-2)^2-20=0
first let’s foil (x-2)
5(x^2-4x+4) -20=0
now distribute the 5
5x^2 -20x +20 -20 = 0
combine like terms
5x^2-20x=0
take the gcf
5x(x-4)=0
x=0, 4
solutions are (4,0) and (2, -20) because the original vertex form a(x-h)^2+k
Answer:
1
Step-by-step explanation:
