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Marrrta [24]
3 years ago
13

Factorise 8x^3+12x^2 y +6xy^2+y^3

Mathematics
2 answers:
devlian [24]3 years ago
4 0

Answer:

Answer:

y(8xy2+12x2+6xy+y2)

Step-by-step explanation:

theres supposed to be a y after 8x^3

tangare [24]3 years ago
3 0

Answer:

(2x+y)^3

Step by step explanation:

(2x)^3+3.(2x.)^2y+3.2x.y^2+(y)^3(Formula of (a+b)^3)

(2x+y)^3

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Madelynne hopped 12 times in 15 seconds.What is her speed in hops per minute?
BabaBlast [244]
60 seconds = 1 minute
60/15 = 4

12 hops in 15 seconds is the same as

4 * 12 hops in 4 * 15 seconds, or

48 hops in 60 seconds, and since 60 sec = 1 min, it equals

48 hops per minute.
7 0
4 years ago
The Wilson family spend $600 per month on groceries for their family.if this is 15% of their monthly budget, then what is their
Alex_Xolod [135]

Answer:

90

Step-by-step explanation:

8 0
3 years ago
What is the solution to8(5-r)/5=-2r
Dmitry [639]

Expand 8(5-r)/5=-2r as indicated: 40 - 8r

----------- = - 2r

5

Multiply both sides by 5, obtaining 40 - 8r = - 10r

Combine like terms: 40 = - 2r

Divide both sides by -2: -20 = r

The solution to 8(5-r)/5=-2r is -20. Verify this by subbing -20 for r in the given equation.

4 0
3 years ago
Read 2 more answers
An equilateral triangle is inscribed in a circle of radius 2r. Express the area A within the circle but outside the triangle as
defon

Answer:

A=8\pi r^2-\dfrac{49\sqrt{3}x^2}{4}\ un^2.

Step-by-step explanation:

An equilateral triangle with the side 7x units is inscribed in a circle of radius 2r units.

1. The area of the circle is

A_{circle}=2\pi (2r)^2=2\pi \cdot 4r^2=8\pi r^2\ un^2.

2. The area of the equilateral triangle is

A_{\triangle }=\dfrac{(7x)^2\sqrt{3}}{4}=\dfrac{49\sqrt{3}x^2}{4}\ un^2.

3. The area A within the circle but outside the triangle is

A=A_{circle}-A_{\triangle}=8\pi r^2-\dfrac{49\sqrt{3}x^2}{4}\ un^2.

7 0
3 years ago
If a wagon wheel has a diameter of 70cm, how many revolutions would it take to travel 66 METERS?
ddd [48]

Answer:

30 revolutions

Step-by-step explanation:

to calculate the revolution of the wheels in 66 metres we need to get the circumference

circumference = 2πr, r = radius (diameter divided by 2) but from the formula of circumference we ca rewrite it as πd= 3.14 x 70 = 219.8cm

next convert 66 metres to cm

100cm = 1m

x= 66m

cross multiply

x= 66m x100cm/1m= 6600cm

revolutions in 66metres = 6600cm/219.8cm = 30.0272975 ≅30 revolutions

6 0
3 years ago
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