The side lengths of triangle are 6 units, 8 units and 10 units.
<u>SOLUTION:
</u>
Given that, we have to find what is the length side of a triangle that has vertices at (-5, -1), (-5, 5), and (3, -1)
We know that, distance between two points 
is given by
Now,
Answer:
Step-by-step explanation:
The coefficients of the x terms are {1, 3, -3}, so the discriminant, b^2 - 4ac, is 3^2 - 4(1)(-3), or 9 + 12, or 21. The positive nature of the discriminant tells us that there are two real, unequal roots. Following the quadratic formula, we get:
-3 ± √21
x = -----------------
2
Hello :
f(x) = (2x-5)/3
<span>f−1(x) = (3x+5)/2
because : f(x) 0 </span>f−1(x) = x and f−1(x) 0 f(x) = x
f(x) 0 f−1(x) = f( f−1(x) ) = f ((3x+5)/2) = (2(3x+5)/2 - 5))/3 = 3x /3 =x
same cacul for : f−1(x) 0 f(x) = x
