Question

Using the quadratic formula to solve x2 + 20 = 2x. what are the values of x?

Answer 1

Answer: The answer is x=1±i√19

Answer 2

Answer:

$1\pm \sqrt{19}i$

Step-by-step explanation:

To solve : $x^2-2x+20=0$

Quadratic Formula :

For quadratic equation of form $ax^2+bx+c=0$, roots are given by

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

On comparing equation $x^2-2x+20=0$ with equation $ax^2+bx+c=0$, we get $a=1\,,\,b=-2\,,\,c=20$

Also, we know that $\sqrt{-1}=i$

So,

$x=\frac{2\pm \sqrt{4-80}}{2}=\frac{2\pm \sqrt{-76}}{2}=\frac{2\pm 2\sqrt{19}i}{2}=1\pm \sqrt{19}i$