Let:
v = Olga's speed
t = the time Anna spent going to school (3 km/hour)
t/2 = the time Anna spent running back home with speed of 6 km/hour
So, t + t/2 = 3t/2 is the total time
In the meantime distance = speed*time and the both made the same distance we can put it as:
3t + 6*(t/2) = (3t/2)*v
6t = (3/2)tv divide both sides by t
(3/2)v = 6
v = 2*6/3
v = 4 km/hour
Olga's speed was 4 km/hour.
2(3+6) = 6 + 12 = 18
10² = 100
10(10+10) = 100 + 100 = 200
Answer:
637
Step-by-step explanation:
Ticket ending 00= £12 * 7 = £84
Tickets ending 5 = £1.5 * 75 = £112.5
£84+£112.5=£196.5
Price money + Profit: £196.5+£163= 356
356/£0.5 = 719 total tickets sold
719- 82 (WINNING TICKETS) = 637 losing tickets sold
N is equal to = 20 which means there were 20 trials. Based on the results, the number of times that the results showed that 1 out of 3 students ride a car going to school, there is 55% probability or 0.55. There are 11 trials out of 20 trials that have exactly 1 student that rides a car going to school.
Answer:
17%, 1/4, 1.7
Step-by-step explanation:
Convert each to decimals: 17% = .17, 1/4 = .25, then order from least to greatest
