All categories

3 years ago

Please help don’t understand

Mathematics

1 answer:

Morgarella [4.7K]3 years ago

6 0

Answer:

r = 4

Step-by-step explanation:

If we clearly observe a point and the slope of the line are given.

Point=(5, -6) slope= -5

We know that the equation of the line having slope m and passing through point ( $x_{1} , y_{1}$ ) is

$y-y_{1}=m(x-x_{1})$

Now the equation of the line is $y-(-6)=(-5)*(x-5)$

$y+6=-5x+25$

$5x+y=19$

Now given that (3,r) lies on this line

$5*3+r=19$

r = 4

You might be interested in

What is the y intercept of the line whose equation is y=1/2x-3

Burka [1]

Answer:

-3

Step-by-step explanation:

y=1/2x-3

y=mx+b where m=slope and b=y-intercept

b=-3

7 0

3 years ago

Please help me grades all most here

Ghella [55]

Answer:

What about

Step-by-step explanation:

SUS :0000

jp I'm pretty sure its asa. forgive me if im wrong.

5 0

3 years ago

Exercises

lyudmila [28]

Answer:

minimum 380 student tickets must be sold.

Step-by-step explanation:

c) 500x7=3500

intended =5400

5400-3500=1900

1900/5= 380

3 0

3 years ago

Using properties of sets show that : a) A ∩ (A’ U B) = A ∩ B b) A ∩ (A U B )’ = Ф

asambeis [7]

Answer:

a) From A ∩ A' = ∅, we have;

A ∩ (A' ∪ B) = A ∩ B

b) From A ∩ (A' ∩ B') = (A ∩ A') ∩ B' and A ∩ A' = ∅, we have;

A ∩ (A ∪ B)' = ∅

Step-by-step explanation:

a) By distributive law of sets, we have;

A ∩ (B ∪ C) = (A ∩ B) ∪ (A ∩ C)

From the complementary law of sets, we have;

A ∩ A' = ∅

Therefore, for A ∩ (A' ∪ B) = A ∩ B, we have

A ∩ (A' ∪ B) = (A ∩ A') ∪ (A ∩ B) (distributive law of sets)

A ∩ A' = ∅ (complementary law of sets)

Therefore;

(A ∩ A') ∪ (A ∩ B) = ∅ ∪ (A ∩ B) = (A ∩ B) (Addition to zero identity property)

∴ A ∩ (A' ∪ B) = A ∩ B

b) By De Morgan's law

(A ∪ B)' = A' ∩ B'

Therefore, A ∩ (A ∪ B)' = A ∩ (A' ∩ B')

By associative law of sets, we have;

A ∩ (A' ∩ B') = (A ∩ A') ∩ B'

A ∩ A' = ∅ (complementary law of sets)

Therefore, (A ∩ A') ∩ B' = ∅ ∩ B' = ∅

Which gives;

A ∩ (A ∪ B)' = ∅.

4 0

3 years ago

In a survey, three out of four students said that courts show too much concern for criminals. Of seventy randomly selected stude

vladimir1956 [14]

Answer:

B. Yes, because P(X ≥ 68) ≤ .05

Step-by-step explanation:

The probability of a score X occuring is said to be unusually high if the probability of a score of X or larger is lower than 5%.

For each student, there are only two possible outcomes. Either they think that the court shows too much concern for criminals, or they do not think this. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

Three out of four students said that courts show too much concern for criminals. This means that $p = \frac{3}{4} = 0.75$

Would 68 be considered an unusually high number of students who feel that courts are partial to criminals?

We have to find $P(X \geq 68)$ .

$P(X \geq 68) = P(X = 68) + P(X = 69) + P(X = 70)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 68) = C_{70,68}.(0.75)^{68}.(0.25)^{2} < 0.000001$

$P(X = 69) = C_{70,69}.(0.75)^{69}.(0.25)^{1} < 0.000001$

$P(X = 70) = C_{70,70}.(0.75)^{70}.(0.25)^{0} < 0.000001$

$P(X \geq 68) = P(X = 68) + P(X = 69) + P(X = 70) < 0.000003$

$P(X \geq 68)$ is lower than 0.05, so this is an unusually high number.

So the correct answer is:

B. Yes, because P(X ≥ 68) ≤ .05

5 0

3 years ago