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Gelneren [198K]
3 years ago
8

Use the quadratic formula to solve the equation​. 4x^2−10x+5=0

Mathematics
1 answer:
finlep [7]3 years ago
5 0

Quadratic formula:

x=\frac{-b±\sqrt{b^{2}-4ac } }{2a}

What do we have:

a=4

b=-10

c=5

Substitude:

x=\frac{10±\sqrt{b^{2}-4(4)(5)}}{2(a)}

Solve:

x=\frac{10±\sqrt{(-10)^{2}-4(4)(5)}}{2(4)}\\\\x=\frac{10±\sqrt{100-4(20)}}{8}\\\\x=\frac{10±\sqrt{100-4(20)}}{8}\\\\x=\frac{10±\sqrt{100-80}}{8}\\\\x=\frac{10±\sqrt{20}}{8}\\\\x=\frac{10±2\sqrt{5 }}{8}\\\\x=\frac{2(±5\sqrt{5) }}{2(4)}

Cancel the common terms:

x=\frac{5±\sqrt{5} }{4}

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Answer please lot's of points.
Svetlanka [38]

Answer:

t≈8.0927

Step-by-step explanation:

h(t) = -16t^2 + 128t +12

We want to find when h(t) is zero ( or when it hits the ground)

0 =  -16t^2 + 128t +12

Completing the square

Subtract 12 from each side

-12  =  -16t^2 + 128t

Divide each side by -16

-12/-16  =  -16/-16t^2 + 128/-16t

3/4 = t^2 -8t

Take the coefficient of t and divide it by 8

-8/2 = -4

Then square it

(-4) ^2 = 16

Add 16 to each side

16+3/4 = t^2 -8t+16

64/4 + 3/4= (t-4)^2

67/4 = (t-4)^2

Take the square root of each side

±sqrt(67/4) =sqrt( (t-4)^2)

±1/2sqrt(67) = (t-4)

Add 4 to each side

4 ±1/2sqrt(67) = t

The approximate values for t are

t≈-0.092676

t≈8.0927

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