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Kamila [148]
3 years ago
5

Solving for y 3x-y=8

Mathematics
2 answers:
Dmitriy789 [7]3 years ago
7 0
3x-8=y
you can't get any futher
JulsSmile [24]3 years ago
5 0
You add -3x to both sides of the equation:
-3x+3x-y=8-3x you get -y = 8-3x
and then you multiply both sides by -1 and you get y = 3x-8
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Translate to an algebraic statement.<br> "The quotient of twice a number and 7 is 20."
Genrish500 [490]

<u>Answer:</u>

  • Translation: 2x/7 = 20

<u>Step-by-step explanation:</u>

  • <em>When we listen to the word "quotient", it means the solution to a division problem. </em>
  • <em>An unknown number that has been multiplied by 2 is in the numerator because it came before the 7 in the statement. </em>
  • <em>The number "7" is in the denominator because it came after the 2x in the statement. </em>
  • <em>The word "is" represents an equal sign.</em>
  • <em>The solution to the division problem (quotient) is 20. </em>

<u><em>If we put these clues together, we get 2x/7 = 20 as our translated equation.</em></u>

<u>Hence, our algebraic statement is 2x/7 = 20. The key is to listen to the statement. </u>

BrainiacUser1357

4 0
3 years ago
What would 9c-6+c be as an equivalent expression
pshichka [43]
-6+10c 
I think, reorder the terms: -6+9c+c= -6+10c
8 0
3 years ago
Evaluate s(t)=∫t−[infinity]||r′(u)||du for the bernoulli spiral r(t)=⟨etcos(8t),etsin(8t)⟩. It is convenient to take −[infinity]
sveta [45]

\vec r(t)=\langle e^t\cos8t,e^t\sin8t\rangle

\|\vec r'(t)\|=\sqrt{(e^t(\cos8t-8\sin8t))^2+(e^t(\sin8t+8\cos8t))^2}=e^t\sqrt{(\cos8t-8\sin8t)^2+(\sin8t+8\cos8t)^2}

\implies\|\vec r'(t)\|=e^t\sqrt{65}

Then

s(t)=\displaystyle\sqrt{65}\int_{-\infty}^te^u\,\mathrm du=\sqrt{65}e^t

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chubhunter [2.5K]
The answer is 6. Not the answer: MSOAKAKAKA
8 0
3 years ago
Solve for x The value of x is
Varvara68 [4.7K]

Answer:

7x+19 = 11x-89

-19. -19

7x= 11x-108

-11x -11x

-4x=-108

x=27

8 0
3 years ago
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