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3 years ago

The weight of an object rounds to 41.3 kilograms select the three posible weights that correctly round to 41.3 kilograms

Mathematics

1 answer:

nekit [7.7K]3 years ago

4 0

Answer:

See Explanation

Step-by-step explanation:

Given

$Weight = 41.3kg$

Required

Determine the weights that approximates to 41.3kg

The options are not given but the question is still solvable

In approximation:

0 - 4 approximates to 0

This implies that:

41.30 to 41.34 approximates to 41.3

Also:

5 - 9 approximates to 1

This implies that:

41.25 to 41.29 approximates to 41.3

Bring the range together, we have:

$Range = 41.25\ to\ 41.34$

<em>Select any three numbers within this range, and you have your answer</em>

Examples are: <em>41.25, 41.28, 41.34</em>\

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Once a large pink ribbon, the sign of the fight against breast cancer, was erected out of pink post-it notes on a billboard.

saul85 [17]

Answer:

Pretty sure the width would be 70

Step-by-step explanation:

3920ft divided by 56 = 70

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3 years ago

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Choose the correct slope of the line that passes through the points (1, −3) and (3, −5).

murzikaleks [220]

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4 years ago

The mean amount of money spent on lunch per week for a sample of 100 students is $21. If the margin of error for the population

Digiron [165]

From the given mean and margin of error, the 99% confidence interval for the mean amount of money spent on lunch per week for all students is:

[$19.5, $22.5].

<h3>How to calculate a confidence interval given the sample mean and the margin of error?</h3>

The confidence interval is given by the sample mean plus/minus the margin of error, hence:

The lower bound is the sample mean subtracted by the margin of error.

The upper bound is the sample mean added to the margin of error.

For this problem, we have that:

The sample mean is of $21.

The margin of error is of $1.50.

Hence the bounds are given as follows:

Lower bound: 21 - 1.50 = $19.50.

Upper bound: 21 + 1.50 = $22.50.

Hence the interval is [$19.50, $22.50].

More can be learned about confidence intervals at brainly.com/question/25890103

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7 0

1 year ago

Solve system of equations<br><img src="https://tex.z-dn.net/?f=x%20%2B%202y%20-%20z%20%3D%204%20%5C%5C%202x%20-%20y%20%2B%203z%2

Natasha2012 [34]

First, using elimination method for eq. 1 and 2 to eliminate one of the variables.

2x - y + 3z = 8

-2x + 3y - 2z = 10

------------------------------

2y + z = 18

z = 18 - 2y

Now eq. 1 and 3, but multiple eq.1 with 2.

2x + 4y - 2z = 8

-2x + 3y - 2z = 10

----------------------------

7y - 4z = 18

Now you have two new equations 7y -4z = 18 and z = 18 - 2y. Solve for y and z, using substitute method.

7y - 4z = 18

7y - 4(18 - 2y) = 18

7y - 72 + 8y = 18

15y = 18+72

y = 90/15

y = 6

Find z using one of the two new equations.

z = 18 - 2y

z = 18 - 2(6)

z = 18 - 12

z = 6

Now you got y and z, find x using any one of the main three equations.

x + 2y - z = 4

X + 2(6) - 6 = 4

x + 12 - 6 = 4

x = 4 - 6

x = -2

Solutions:

x = -2

y = 6

z = 6

3 0

4 years ago

HELP what's the distance for this question?

jeyben [28]

Answer:

$Distance = 38.57ft$

Step-by-step explanation:

Given

$Base = 60$

$\theta = 50$

Required

The distance between the top and John

The distance is calculated using:

$sin\alpha = \frac{Distance}{Base}$

Where

$\alpha = 90 - \theta$ --- the angle between the diagonal line and the vertical line

$\alpha = 90 - 50$

$\alpha = 40$

So, we have:

$Sin(40) = \frac{Distance}{60}$

$Distance = 60 * sin(40)$

$Distance = 60 * 0.6428$

$Distance = 38.57ft$

$Distance = 986 * tan(38)$

$Distance = 986 * 0.7812$

$Distance = 770ft$ <em> --- approximated</em>

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3 years ago