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NeX [460]
2 years ago
9

Which of the following inequalities matches the graph? 100 point

Mathematics
2 answers:
netineya [11]2 years ago
8 0
<h2>Question:</h2>

Which of the following inequalities matches the graph?

<h2>Answer:</h2>

Looking at the graph the y values does not change, it stays at zero

The shaded area are the numbers under O

This means the answer is y ≤ 0

<h3>The answer is y ≤ 0</h3>

Hope it helps

-------☆゚.・。゚ᵴɒƙυᴚᴀ_ƨȶäᴎ❀

solong [7]2 years ago
3 0
Y<0 is the inequality. The line is on 0 on the y axis. And it’ll be < since the shaded section is is at the bottom. It’ll be > if the top is shaded.
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Step-by-step explanation:

Si en cuatro vasos es un litro y cada integrante de la familia consume 2 litro diarios, la operacion seria 5 × 2 = 10 Por que son cinco integrantes de la familia y cada uno consume dos diarios entonces consumen 10 litro diarios

ESPERO Y TE AYUDE ;)

8 0
2 years ago
Which values of A and B make the following equations true?
Korolek [52]
<span>(5x^7 y^2)(-4x^4 y^5) =-20x^a y^b
</span><span>
solve this:
(5x^7 y^2)(-4x^4 y^5)
= -20 x^(7 + 4) y^(2 + 5)
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answer

</span>A) a=11, b=7
5 0
3 years ago
How do you do 1/8 the sum of 23 and 17
Mariulka [41]
\sf 23+17=40 \\ \\  \frac{1}{8}*40= \frac{40}{8}=\boxed{\sf 5}
6 0
3 years ago
Read 2 more answers
The area of a rectangle is 56 cm. The length is 2 cm more than x and the width is 5 cm less than twice x. Solve for x. Round to
mr Goodwill [35]
I hope this helps you


l=x+2


w=2x-5



(x+2)(2x-5)=56


2x^2-x-10=56


2x^2-x-66=0


2x +11


x -6



(2x+11)(x-6)=0


x=6
6 0
3 years ago
Determine the value of each expression.<br> i11=
Basile [38]

Answer:

11 * I

Unless you can tell me what I is equal to, I can't give you a number as an answer. Just take what ever I is equal to, an multiply it by 11. If the answer choices are equations rather than numbers, than just say 11 * 1.

If the question comes with any more information, please comment so I can give you a stronger answer.

Hope this helps! :)

              -Sophia

7 0
3 years ago
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