Question

PLZ HELP GIVING OUT BRAINLIEST!!!!

Answer 1

The answer i think is 3

Answer 2

The correct option will be : $\frac{\sqrt[4]{24x^3}}{2x}$

Explanation

$\sqrt[4]{\frac{3}{2x}} = \frac{\sqrt[4]{3}}{\sqrt[4]{2x}}$

For rationalizing the denominator, first we will multiply both up and down by $\sqrt[4]{2x}$. So,

$\frac{\sqrt[4]{3}}{\sqrt[4]{2x}} *\frac{\sqrt[4]{2x}}{\sqrt[4]{2x}} \\ \\= \frac{\sqrt[4]{6x}}{\sqrt[4]{4x^2}}$

Now we will multiply up and down by $\sqrt[4]{4x^2}$. So, we will get...

$\frac{\sqrt[4]{6x}}{\sqrt[4]{4x^2}} *\frac{\sqrt[4]{4x^2}}{\sqrt[4]{4x^2}} \\ \\ = \frac{\sqrt[4]{24x^3}}{\sqrt[4]{16x^4}} \\ \\ = \frac{\sqrt[4]{24x^3}}{2x}$