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Trava [24]
3 years ago
12

At the local pet store, zebra fish cost $1.85 each and neon tetras cost $2.10 each. If Yumi bought 11 fish for a total cost of $

21.60, not including tax, how many of each type of fish did she buy?
Mathematics
2 answers:
Alenkinab [10]3 years ago
6 0

Answer: 5 neon tetras and 6 zebra fish


Step-by-step explanation: it's really hard to explain but I bet you it right doe


Andrews [41]3 years ago
3 0
She bought 6 zebra fish and 5 neon tetras


explanation you add up 1.85 6 times to get 11.10 then you add 2.10 till you get your total 21.60$
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Hey there! We are given two decimal numbers to compare.

52.311 and 52.31

These two numbers are similar except that 52.311 has another 1 in while 51.31 doesn't.

Keep in mind that 52.31 can also refer to 52.310

So we are comparing 52.311 and 52.310

Since 1 is greater than 0.

52.311 is greater than 52.31 (52.311 > 52.31)

Let me know if you have any questions!

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Answer:

5

Step-by-step explanation:

1) Solve for the slope(m):

(y2-y1) / (x2-x1)

pick any

(-3 - (-5) )/ (1 - 0)

(-3 + 5) / (1 - 0)

2/1 = 2

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A manufacturer of golf equipment wishes to estimate the number of left-handed golfers. A previous study indicates that the propo
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Answer:

A sample of 997 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

A previous study indicates that the proportion of left-handed golfers is 8%.

This means that \pi = 0.08

98% confidence level

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How large a sample is needed in order to be 98% confident that the sample proportion will not differ from the true proportion by more than 2%?

This is n for which M = 0.02. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.02 = 2.327\sqrt{\frac{0.08*0.92}{n}}

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\sqrt{n} = \frac{2.327\sqrt{0.08*0.92}}{0.02}

(\sqrt{n})^2 = (\frac{2.327\sqrt{0.08*0.92}}{0.02})^2

n = 996.3

Rounding up:

A sample of 997 is needed.

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3 years ago
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