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3 years ago

Select the number that would make this statement true: 628 divided by 0.628

Mathematics

1 answer:

Amiraneli [1.4K]3 years ago

8 0

The answer would be 10 to the third because if you divide that it would equal 1,000

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Anyone know the right answer?!

sleet_krkn [62]

Answer:

420000 here is the answer

Step-by-step explanation:

28000 multipli 15

5 0

3 years ago

for a triangle to be obtuse only one of the angles must br shown to be obtuse. (in fact only one of the angles can possibly be o

Alchen [17]

Answer:

The explanation is given below.

Step-by-step explanation:

Given for a triangle to be obtuse only one of the angles must be shown to be obtuse but for a triangle to be acute all three angles must be shown to be acute.

According to Pythagoras theorem for a right angled triangle which has one angle of 90° rest of two are acute.

$a^{2}+b^{2}=c^{2}$

Hence, by Pythagorean inequality

$a^{2}+b^{2}>c^{2}$

which gives the triangle is acute.

Hence, one acute angle with the Pythagorean inequalities theorem shows that the triangle is acute.

5 0

3 years ago

1011+111 in binary form

Ann [662]

Answer:

10010

Step-by-step explanation:

$1011=1(2)^3+0(2)^2+1(2)^1+1(2)^0$

$111=1(2)^2+1(2)^1+1(2)^0$

So $1011+111$ gives us:

$1(2)^3+0(2)^2+1(2)^1+1(2)^0$

$+$

$1(2)^2+1(2)^1+1(2)^0$

-----------------------------------------------------

Combine like terms:

$1(2)^3+(0+1)(2)^2+(1+1)(2)^1+(1+1)(2)^0$

$1(2)^3+1(2)^2+(2)(2)^1+(2)(2)^0$

We aren't allowed to have a coefficient bigger than 1.

I'm going to replace $2^0$ with 1 and $2$ with $(2)^1$ :

$1(2)^3+1(2)^2+(2)^2+(2)^1(1)$

I want a $2^0$ number:

$1(2)^3+1(2)^2+1(2)^2+1(2)^1+0(2)^0$

Combine like terms:

$1(2)^3+2(2)^2+1(2)^1+0(2)^0$

$2(2)^2=2^3$ :

$1(2)^3+2^3+1(2)^1+0(2)^0$

Combine like terms:

$2(2)^3+1(2)^1+0(2)^0$

We can rewrite the first term by law of exponents:

$2^4+1(2)^1+0(2)^0$

$1(2)^4+1(2)^1+0(2)^0$

So the binary form is:

$10010$

Maybe you like this way more:

Keep in mind 1+1=10 and that 1+1+1=11:

Setup:

1 0 1 1

+ 1 1 1

------------------------------

(1) (1) (1)

1 0 1 1

+ 1 1 1

------------------------------

1 0 0 1 0

I had to do some carry over with my 1+1=10 and 1+1+1=11.

8 0

3 years ago

Solve the following equation system by graphing X-Y=4 X+Y=2 What is the solution?

AfilCa [17]

X-Y=4,
X+Y=2
-------------add
2x = 6
x = 3

X - Y =4
3 - Y = 4
Y = 3 - 4
Y = -1

solution (3 , -1)

4 0

3 years ago

Porfavor: 5(x+9) = 2(x+30)= cuanto es?

MrMuchimi

Step-by-step explanation:

Primero encontramos el valor de x,

5(x+9) = 2(x+30)

=> 5x + 45 = 2x + 60

=> 5x - 2x = 60 - 45

=> 3x = 15

$= > x = \frac{15}{3}$

=> x = 5

Como tenemos el valor de x entonces,

LHS = 5(x+9) RHS = 2(x+30)

= 5(5+9) = 2(5+30)

= 5 × 14 = 70. = 2 × 35 = 70

Por tanto, el valor es,

5 (x + 9) = 2 (x + 30) = 70 (Ans)

7 0

3 years ago