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valentinak56 [21]
3 years ago
8

I need help fast ....​

Mathematics
1 answer:
Cloud [144]3 years ago
4 0
Since x=-10, plug that into the equation.

f(x) = 2(-10) + 11
= -20 + 11
y = -9

So the ordered pair in (x,y) terms is (-10,-9).
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Which of the following is a property of all squares?
Ivanshal [37]

Answer:

Option D) is correct

That is Option D) "The diagonals bisect each other" is correct

Step-by-step explanation:

The property of all squares is

"The diagonals of a square bisect its angles" and it can be written also also as below

"The diagonals bisect each other"

Therefore Option D) is correct

That is Option D) "The diagonals bisect each other" is correct

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The perimeter of a rectangle is 14 11/12 feet.if the length is 4 3/8 feet what ia the width
Gnom [1K]

Perimeter = 179/12 feet

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Step-by-step explanation:

3 0
4 years ago
Read 2 more answers
A particle moves with velocity vector
asambeis [7]

Answer:

\vec{s(t)}=\frac{1}{2}t^2\hat{i}-(2t+1)\hat{j}+(\frac{1}{3}t^3+1)\hat{k}

Step-by-step explanation:

We are given that velocity vector of a particle

\vec{v(t)}=t\hat{i}-2\hat{j}+t^2\hat{k}

When t=0 then the particle is at the point (0,-1,1).

We have to find the position of particle  at time t.

We know that

Velocity =\frac{Displacement }{time}=\frac{ds}{dt}

Therefore,\vec{v}=\frac{\vec{ds}}{dt}

\int{ds}=\int (t\hat{i}-2\hat{j}+t^2\hat{k})dt

Integrate on both sides then we get

\vec{s(t)}=\frac{1}{2}t^2\hat{i}-2t\hat{j}+\frac{1}{3}t^3\hat{k}+C

\int x^n dx=\frac{x^{n+1}}{n+1}+C

Substitute the value of point at time t=0 then we get

C=-\hat{j}+\hat{k}

Substitute the value of C then we get

\vec{s(t)}=\frac{1}{2}t^2\hat{i}-2t\hat{j}+\frac{1}{3}t^3\hat{k}-\hat{j}+\hat{k}

Therefore, the position of particle at time t

\vec{s(t)}=\frac{1}{2}t^2\hat{i}-(2t+1)\hat{j}+(\frac{1}{3}t^3+1)\hat{k}

8 0
3 years ago
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