Question

Write a C++ program that computes the area and perimeter of aspecified shape

Answer 1

C++ program that computes the area and perimeter of a specified shape

#include <iostream>

#include <cmath>

using namespace std;

void rectangle() //Defining function for rectangle

{ int h,w;

cout << "Enter height: ";

//taking input

cin >> h;

cout << "Enter width: ";

cin >> w;

cout << "The perimeter of the rectangle is " <<2*h+ 2*w << " and the area is " <<h*w << endl;  //printing output

}

void triangle()  //Defining function for triangle

{ int s1,s2,s3,h,w;

cout << "Side 1: ";  //Taking input

cin >> s1;

cout << "Side 2: ";

cin >> s2;

cout << "Side 3: ";

cin >> s3;

cout << "Enter the height: ";

cin >> h;

cout << "Enter the base length: ";

cin >> w;

cout << "The perimeter of the triangle is " <<s1+s2+s3 << " and the area is " <<(.5)*w*h << endl; //printing output

}

void circle()//Defining Function for the circle

{

const double p=3.14;

int w;

cout << "Enter the radius: "; //Taking input

cin >> w;

cout << "The perimeter of the circle is " << p*2*w << " and the area is " << p*w*w<< endl;  //printing output

}

int main()  //driver function

{

int s;

cout << "Enter the shape (1 for rectangle,2 for triangle, 3 for circle): ";

//Asking user for the shape

cin >> s;

switch(s)  //checking which shape it chooses

{

case 1:

rectangle();  //If user type 1 ,then calling rectangle function

break;

case 2:

triangle();   //If user type 2 ,then calling triangle function

break;

case 3:

circle();  //If user type 3,then calling circle function

break;

default:

cout <<"Enter valid choice for shape";  //If user type other than 1,2,3

}

return 0;  

}

Output

Enter the shape (1 for rectangle,2 for triangle, 3 for circle): 1

Enter height:2

Enter width: 3

The perimeter of the rectangle is 10 and the area is 6