Zybook C++ 3.21 answer

List the three control problems associated with competingprocesses and briefly define each.

hjlf

Answer and explanation :

the three control problems associated with competing process are

MUTUAL EXCLUSION : We know that some resources are shareable and some are not shareable. which means only one process can access the resource at a time this type of resources are called critical resources this code can be access at only one process at a time. the other process if required to access should not be allowed
DEADLOCK: this hold the process without complete for example suppose there are two resources R1 and R2 and two process P1 and P2 and P1 use R1 and P2 use R2 but after some time when P1 needs R2 but R2 is not available as it is used by P2 so the all process will be on hold
STARVATION : when priorities are given to the process as high priorities and low priorities. And high priorities process always competing then low priorities process have to wait for very long time this is called starvation

3 0

3 years ago

If i find an image and copy and paste it into Paint.

Leokris [45]

Answer:

Lossy image formats will remove data during compression as a trade off for lower storage occupation. Lossless data formats will not remove data during compression, resulting in higher quality but also higher storage occupation.

Graphic Artists will almost always use lossless due to it delivering the highest quality image possible.

8 0

4 years ago

I need help with completing this python code.Complete the Car class by creating an attribute purchase_price (type int) and the m

netineya [11]

Answer:

class Car:

def __init__(self):

self.model_year = 0

# TODO: Declare purchase_price attribute

self.purchase_price = 0

self.current_value = 0

def calc_current_value(self, current_year):

depreciation_rate = 0.15

# Car depreciation formula

car_age = current_year - self.model_year

self.current_value = round(self.purchase_price * (1 - depreciation_rate) ** car_age)

# TODO: Define print_info() method to output model_year, purchase_price, and current_value

def print_info(self):

print("Model year: ",self.model_year)

print("Purchase year: ",self.purchase_price)

print("Current value: ",self.current_value)

def main():

year = int(input())

price = int(input())

current_year = int(input())

my_car = Car()

my_car.model_year = year

my_car.purchase_price = price

my_car.calc_current_value(current_year)

my_car.print_info()

if __name__ == "__main__":

main()

Explanation:

The Car class in the python program is used to create a car object instance with class methods model_year, purchase_price, and calc_current_value, which accepts as arguments, year, price and current_year respectively. The main function runs if only the python module is run and interpreted to print out the year and current price of a car object instance defined.

4 0

3 years ago

1. It is a requirement to install a routing protocol that monitors the network for routers that have changed their link state. T

Nady [450]

Answer:

1. Open Shortest Path First (OSPF)

2. Border Gateway Protocol (BGP)

3. Routing and Remote Access Service (RRAS)

4. Frame relay

5. Synchronous

6. Virtual

7. Committed Information Rate (CIR)

8. Integrated Services Digital Network (ISDN)

9. Asynchronous Transfer Mode (ATM)

10. Basic Rate Interface (BRI).

8 0

3 years ago

Flowgorithm, Design a program that prompts the user to enter a number within the range of 1 through 10. The program should displ

kherson [118]

Answer:

Step by step code along with explanation and output is given below

Explanation:

We can solve this problem using if elif else approach

def main():

# prompts the user to enter an integer from 1 to 10

num = int (input('Enter a number in the range of 1 to 10:\n'))

# using the if elif print out the roman numeral from 1 to 10

if num == 1:

print ('Roman Numeral for 1 is I')

elif num == 2:

print ('Roman Numeral for 2 is II')

elif num == 3:

print ('Roman Numeral for 3 is III')

elif num == 4:

print ('Roman Numeral for 4 is IV')

elif num == 5:

print ('Roman Numeral for 5 is V')

elif num == 6:

print ('Roman Numeral for 6 is VI')

elif num == 7:

print ('Roman Numeral for 7 is VII')

elif num == 8:

print ('Roman Numeral for 8 is VIII')

elif num == 9:

print ('Roman Numeral for 9 is IX')

elif num == 10:

print ('Roman Numeral for 10 is X')

# using the else print out error message whenever user enters any other number not listed above

else:

print ('Error! Wrong Input')

# call the main function

main()

Output:

Enter a number in the range of 1 to 10:

6

Roman Numeral for 6 is VI

Enter a number in the range of 1 to 10:

15

Error! Wrong Input

6 0

3 years ago