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fredd [130]
3 years ago
15

Tom has 100 baseball cards and 120 football cards. What is the ratio of baseball cards to football cards?

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
5 0
The ratio is 100:120 since you are doing baseball cards: football cards. the simplified ratio is 5:6.
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Quadrilateral ABCD is similar to Quadrilateral EFGH. Diagonal AC has length 7 and diagonal EG has length 13. What is the scale f
olasank [31]

Answer:

\large \boxed{\text{A. }\dfrac{13}{7}\text{; B. }\dfrac{17}{14} \text{; C. 507 in}^{2}}

Step-by-step explanation:

A. Scale factor

When you dilate an object by a scale factor, you multiply its line lengths by the same number.

If EF/AB = 13/7, the scale factor is 13/7.

B. Length of EF

\begin{array}{rcl}\dfrac{EF}{AB} & = & \dfrac{13}{7}\\\\\dfrac{EF}{\frac{17}{26}} & = & \dfrac{13}{7}\\\\EF & = & \dfrac{13}{7}\times\dfrac{17}{26}\\\\ & = &\dfrac{1}{7}\times\dfrac{17}{2}\\\\ & = & \mathbf{\dfrac{17}{14}}\\\end{array}\\\text{The length of EF is $\large \boxed{\mathbf{ \dfrac{17}{14}}}$}

C. Area of EFGH

If the lengths in a shape are all multiplied by a scale factor, then the areas will be multiplied by the scale factor squared.

ABCD is dilated by a scale factor of 13/7, so its area is dilated by a scale factor of

\left(\dfrac{13}{7} \right)^{2} = \dfrac{169}{49}

The area of its dilated image EFGH is

\text{Area of EFGH} = \text{147 in}^{2} \times \dfrac{\text{169}}{\text{49}} = 3 \times 169\text{ in}^{2} = 507 \text{ in}^{2}\\\\\text{The area of EFGH is $\large \boxed{\textbf{507 in}^{\mathbf{2}}}$}

8 0
3 years ago
The number of calories burned while jogging varies directly with the number of minutes spent jogging. If george burns 150 calori
IRISSAK [1]
He will burn 225 calories. if you divide 150/20 it will equal 7.5 then multiply 7.5 by 30 and you’ll get 225
7 0
3 years ago
A cheer squad of 8 cheerleaders raised $317.30. They need $622.42 to
adell [148]

Answer:

Each cheerleader needs to raise 38.14 more

Step-by-step explanation:

6 0
2 years ago
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A meteorologist who sampled 4 thunderstorms found that the average speed at which they traveled across a certain state was 16 mi
DENIUS [597]

Answer:

The  90 % confidence  interval  for the mean population is (11.176  ; 20.824 )

Rounding to at least two decimal places would give 11.18 , 20.83

Step-by-step explanation:

Mean = x`= 16 miles per hour

standard deviation =s= 4.1 miles per hour

n= 4

\frac{s}{\sqrt n}  =  4.1/√4= 4.1/2= 2.05

1-α= 0.9

degrees of freedom =n-1=  df= 3

∈ ( estimator  t with 90 % and df= 3 from t - table ) 2.353

Using Students' t - test

x`±∈ * \frac{s}{\sqrt n}

Putting values

16 ± 2.353 * 2.05

= 16 + 4.82365

20.824  ;        11.176

The  90 % confidence  interval  for the mean population is (11.176  ; 20.824 )

Rounding to at least two decimal places would give 11.18 , 20.83

4 0
3 years ago
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I NEED HELP WITH MATH QUESTION PLEASE HELP ME NO LINKS !!!
lukranit [14]

Answer:

21.8

Step-by-step explanation:

1.9 + 9 = 10.9

10.9 x 2 = 21.8

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2 years ago
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