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wlad13 [49]
3 years ago
9

The denominator of a fraction is three more than the numerator. When both are increased by 1 the fraction becomes 1/2. What is t

he original fraction?
Mathematics
1 answer:
Akimi4 [234]3 years ago
8 0

Answer:

2/5

Step-by-step explanation:

Let x = numerator

3 + x = denominator

\frac{x}{3+x}

the numerator and denominator are increased by 1 , the fraction becomes

\frac{x + 1}{4 + x} = \frac{1}{2}

cross multiply

2(x + 1 ) = 4 + x

2x + 2 = 4 + x

combine like terms

2x - x = 4 - 2

x = 2 = numerator

denominator = 2 + 3 = 5

2/5 fraction

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3 years ago
For number 6, evaluate the definite integral.
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\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{(8+2x)^2}}\cdot dx\impliedby \textit{now, let's do some substitution}\\\\
-------------------------------\\\\
u=8+2x\implies \cfrac{du}{dx}=2\implies \cfrac{du}{2}=dx\\\\
-------------------------------\\\\

\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{u^2}}\cdot \cfrac{du}{2}\implies \cfrac{1}{2}\int\limits_{0}^{28}\ u^{-\frac{2}{3}}\cdot du\impliedby 
\begin{array}{llll}
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\textit{by using } u(x)
\end{array}\\\\
-------------------------------\\\\
u(0)=8+2(0)\implies u(0)=8
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\bf \\\\
-------------------------------\\\\
\displaystyle  \cfrac{1}{2}\int\limits_{8}^{64}\ u^{-\frac{2}{3}}\cdot du\implies \cfrac{1}{2}\cdot \cfrac{u^{\frac{1}{3}}}{\frac{1}{3}}\implies \left. \cfrac{3\sqrt[3]{u}}{2} \right]_8^{64}
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3 years ago
Triangle abc is similar to triangle FGH solve for p plebs.
12345 [234]

The value of <em>p </em>is 21

Step-by-step explanation:

ΔABC ~ ΔFGH

\frac{ab}{fg}  =  \frac{bc}{gh}  \\  \frac{35}{p}  =  \frac{10}{6}  \\ p =  \frac{35 \times 6}{10}  \\ p =  \frac{210}{10}  \\ p = 21 \\  \\ or \\  \\  \frac{ab}{fg}  =  \frac{ac}{fh}  \\  \frac{35}{p}  =  \frac{30}{18}  \\ p =  \frac{35 \times 18}{30}  \\ p =  \frac{630}{30}  \\ p = 21

So, the value of <em>p</em> is 21

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