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3 years ago

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Jacob and Sarah are saving money to go on a trip. They need at least $2000 in order to go. Jacob mows lawns and Sarah walks dogs

to raise money. Jacob charges $20 each time he mows a lawn and Sarah charges $10 each time she walks a dog.
Write an inequality to model the problem, with x representing the number of lawns mowed and y representing the number of dogs walked.

1 answer:

Paladinen [302]3 years ago

7 0

Answer:

$20x+10y\ge 2000$

Step-by-step explanation:

Let x represent the number of lawns Jacob mowed and y represent the number of dogs Sarah walked.

Jacob charges $20 each time he mows a lawn, then he earns $20x for x lawns mowed.

Sarah charges $10 each time she walks a dog, then she earns $10y for y dogs walked.

In total, they will earn $(20x + 10y). They need at least $2000 in order to go on a trip, then

$20x+10y\ge 2000$

Note that $x\ge 0,\ y\ge 0.$

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What +2/3=11/12 equation

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Answer:

1/4

Step-by-step explanation:

1st: you need to make a common denominator for 2/3 and 11/12 that would be 12, so you would keep 11/12 how it is but multiply the numerator and the denominator by 4 to get it to 12.

You would have ;

8/12+___=11/12

Then just do 11/12-8/12

so that would simplify out to 1/4

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saveliy_v [14]

Answer:

(x,y) --> (x+4, y-5)

Step-by-step explanation:

A is correct. B can be represented as x+4, y - 5 because the x values shifted 4 to the right (a positive shift so x+4) and the y values shifted 5 down (a negative shift so y-5)

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consider the function f(x) = x2 2x – 15. what are the x-intercepts of the function? left-most x-intercept: ( , 0) right-most x-i

eimsori [14]

we have

$f(x)=x^{2} +2x-15$

we know that

The x-intercept is the value of x when the value of the function is equal to zero

so

in this problem

Find the roots of the function

equate the function to zero

$x^{2} +2x-15=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2} +2x=15$

Complete the square. Remember to balance the equation by adding the same constants to each side

$x^{2} +2x+1=15+1$

$x^{2} +2x+1=16$

Rewrite as perfect squares

$(x+1)^{2}=16$

Square root both sides

$(x+1)=(+/-)\sqrt{16}$

$(x+1)=(+/-)4$

$x=-1(+/-)4$

$x1=-1+4=3$

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the x-intercepts are the points $(3,0)$ and $(-5,0)$

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Write the equation of the line that passes through the points (-6,5) and (3,−5). Put your answer in fully reduced point-slope fo

elena55 [62]

Answer:

$\displaystyle y-5=-\frac{10}{9}(x+6)$

Or:

$\displaystyle y+5=-\frac{10}{9}(x-3)$

Step-by-step explanation:

We want to write the equation of a line that passes through the points (-6, 5) and (3, -5) in point-slope form.

Point-slope form is given by:

$y-y_1=m(x-x_1)$

Thus, first, we need to find the slope. We can use the slope formula:

$\displaystyle m=\frac{\Delta y}{\Delta x}=\frac{(-5)-(5)}{(3)-(-6)}=\frac{-10}{9}=-\frac{10}{9}$

Next, we can use either of the two given points. I'll use (-6, 5). So, let (-6, 5) be (<em>x₁, y₁</em>). Substitute:

$\displaystyle y-(5)=-\frac{10}{9}(x-(-6))$

Or, fully simplified:

$\displaystyle y-5=\frac{-10}{9}(x+6)$

Using the other point, we will acquire:

$\displaystyle y-(-5)=-\frac{10}{9}(x-(3))$

Or, simplified:

$\displaystyle y+5=-\frac{10}{9}(x-3)$

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