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zaharov [31]
3 years ago
9

What is the working principle of computer?

Computers and Technology
1 answer:
ankoles [38]3 years ago
8 0
The CPU is the working principle
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<em>☆</em><em> </em><em>STATEMENT</em><em> </em><em>WILL</em><em> </em><em>BE</em><em> </em><em>EXECUTED</em><em> </em><em>DEPEND</em><em> </em><em>UPON</em><em> </em><em>THE</em><em> </em><em>OUTPUT</em><em> </em><em>OF</em><em> </em><em>THE</em><em> </em><em>EXPRESSION</em><em> </em><em>INSIDE</em><em>. </em>

<em>☆</em><em> </em><em>IF</em><em> </em><em>THE</em><em> </em><em>STATEMENT</em><em> </em><em>EVALUATES</em><em> </em><em>INTEGER</em><em>, </em><em>CHARACTER</em><em>, </em><em>POINTER</em><em>《</em><em> </em><em>OR</em><em> </em><em>》</em><em>FLOATING-</em><em> </em><em>POINT</em><em> </em><em>TYPE</em><em> </em><em>《</em><em> </em><em>OR</em><em> </em><em>》</em><em>BOOLEAN</em><em> </em><em>TYPE</em><em>. </em>

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3 years ago
Fifty-three percent of U.S households have a personal computer. In a random sample of 250 households, what is the probability th
aleksley [76]

Answer:

The correct Answer is 0.0571

Explanation:

53% of U.S. households have a PCs.

So, P(Having personal computer) = p = 0.53

Sample size(n) = 250

np(1-p) = 250 * 0.53 * (1 - 0.53) = 62.275 > 10

So, we can just estimate binomial distribution to normal distribution

Mean of proportion(p) = 0.53

Standard error of proportion(SE) =  \sqrt{\frac{p(1-p)}{n} } = \sqrt{\frac{0.53(1-0.53)}{250} } = 0.0316

For x = 120, sample proportion(p) = \frac{x}{n} = \frac{120}{250} = 0.48

So, likelihood that fewer than 120 have a PC

= P(x < 120)

= P(  p^​  < 0.48 )

= P(z < \frac{0.48-0.53}{0.0316}​)      (z=\frac{p^-p}{SE}​)  

= P(z < -1.58)

= 0.0571      ( From normal table )

6 0
3 years ago
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