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anzhelika [568]
3 years ago
7

IBF Consultants, LLC provides consulting services in privacy and theft deterrence solutions. Another client has very sensitive d

ata and they are less concerned about recovering any stolen computer than ensuring that the data located on the computer is not compromised. Which technology would be useful in this case?
Computers and Technology
1 answer:
vichka [17]3 years ago
5 0

Answer:

In this case, The kill switch hard drives should be used.

Explanation:

The USB Kill switch is an anti forensic software that is distributed by the GitHub and it is written in the Python Programming Language for the Linux, BSD, and OS X operating system. It designed to serve to kill switch if the computer system on which it installs should be fall under control of an individual or the entities the owners or the operators don't wish it to.  

It is the free software that is available under the General Public License (GNU).

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What is one disadvantage people face without a checking account?
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Programming challenge description: Given a string comprising just of the characters (,),{,},[,] determine if it is well-formed o
nadezda [96]

Answer:

Employing Java language,

Explanation:

//for using stack data structure

import java.util.Stack;

//class definition

public class BracketMatch {

   //function to find the string is well formed or not

   public static boolean isWellFormed(String str) {

       //variable to store the character value

       char ch;

       //check if the first character itself is the end of the brackets

       if (str.charAt(0) == ')'||str.charAt(0) =='}'||str.charAt(0) ==']')

           return false;

       //creating a stack of character type

       Stack<Character> stack = new Stack<Character>();

       //iterating through the characters in string

       for(int i=0; i < str.length(); i++) {

           //storing the current character from the string in the variable

           ch = str.charAt(i);

           if(ch == '('||ch=='{'||ch=='[')

               //if the character is starting of the brackets push it into stack

               stack.push(ch);

           else if(ch == ')')

               //if it is closing bracket and the stack is empty then the string is not well formatted

               if(stack.empty())

                   return false;

               else if(stack.peek() == '(')

                   stack.pop();

               else

                   return false;

           else if(ch == '}')

               if(stack.empty())

                   return false;

               else if(stack.peek() == '{')

                   stack.pop();

               else

                   return false;

       }

       //returning the stack content, if the string will be well formed the stack would be empty

       //after all the operations

       return stack.empty();

   }

   //main method

   public static void main(String[] args) {

       //calling function to find if the string is welll formatted or not

       System.out.println(isWellFormed("{}"));

       //calling function to find if the string is welll formatted or not

       System.out.println(isWellFormed("([)]"));

   }

}

5 0
3 years ago
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gregori [183]

Answer:

yes

Explanation:

because the people will be lazy to go and talk to that person instead They will call each other and discuss

7 0
2 years ago
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