The answer is i know this because, if the answer was, let’s say then it’ll equal 24 which is incorrect.
Answer:
6/7 ≈ 85.7%
Step-by-step explanation:
The probability that a 0 was transmitted and received is 0.5·0.9 = 0.45.
The probability that a 1 was transmitted and a 0 received is 0.5·0.15 = 0.075.
Then the probability that a 0 was received is 0.45 +0.075 = 0.525.
The probability of interest is ...
p(0 transmitted | 0 received) = p(0 transmitted & received)/p(0 received)
= 0.45/0.525 = 6/7 ≈ 85.7%
3y+y+6y
Notice that all these terms have the 'y' variable in them, meaning they are all like terms.
'y' by itself acts as a One, when adding it to other like terms.
3y+6y=9y
Then, add the singular y to the equation = 9y+y=10y
Answer:
Step-by-step explanation:
hello,
I understand that there are only 4 cards and then the player draw a card out of the 4 cards, replace it so the second draw is still out of the 4 cards
<u>How many ways can you draw two cards?</u>
as the first card is replaced, this is 4*4=16
so there is 16 possibles ways
hearts hearts
hearts clubs
hearts diamonds
hearts spades
clubs hearts
clubs clubs
clubs diamonds
clubs spades
diamonds hearts
diamonds clubs
diamonds diamonds
diamonds spades
spades hearts
spades clubs
spades diamonds
spades spades
<u>out of these 16 ways, how many have same colour for both cards?</u>
I assume that there are only two colours Red and Black, so we can have
only 8 ways so the first probability is 8/16 = 1/2
<u>out of these 16 ways, how many are red ace first and black ace?</u>
There are 4 ways so the probability is 4/16 = 1/4
hope this helps