A) The total number is the sum of all the frequencies
2+5+8+12+11+6=44
Answer: 44
B) The width is (upper limit - lower limit) / 2
(35-21) / 2 = 7
(50-36) / 2 = 7
(65-51) / 2 = 7
(80-66) / 2 = 7
(95-81) / 2 = 7
(110-96) / 2 = 7
Answer: the width is 7
C) The midpoint is the lower limit + the width
36+7=43
Answer: the midpoint is 43
D)The modal is the class with more frequency
In this case 66-80 with 12
Answer: class 66-80
E) We use the width formula
lower limit = 111
width = 7
upper = (width * 2) - lower
upper = (7 * 2) + 111
upper = 125
Answer: class 111-125
Adjacent right angles are Never complementary
The answer is B because if you convert all of them to decimals you get it in that order.
<h3>
Answer: B) 10pi</h3>
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Explanation:
AB is a diameter of the circle with point O in the center. This makes angle AOB to be 180 degrees. Consequently, arc ADB makes up 180 degrees of a full 360 degree circle (ie it makes up half of the circle since 180/360 = 1/2)
We're told that arc ADB is 15pi units long. Since arc ADB makes up half the circle, the full circle must therefore be 2*15pi = 30pi. This is the circumference.
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We're also told that angle COB is 60 degrees. Let's find angle COA
(angleCOA) + (angleCOB) = 180
angleCOA = 180-(angleCOB)
angleCOA = 180-60
angleCOA = 120
Angle COA is 120 degrees
This makes up 120/360 = 1/3 of the full circle
So (1/3)*(circumference) = (1/3)*(30pi) = 10pi is the arc length of AC where we take the shorter path from A to C along the circle's edge.
