What is 5c-4c+c-3c and 3a+6+5a-2 and 8b+8-4b-3?
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Answer:
<u><em>Hours</em></u> 0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0 4.5 5.0
<u><em>Frequency</em></u>* 0.2 0.09 0.25 0.18 0.11 0.07 0.05 0.02 0.01 0.02 0.01
Problem Statement:
The table shows the number of hours, to the nearest half hour per day, that teens spend texting according to a random sample of 870 teenagers aged 13–18 in a large urban city.
Hours 0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0 4.5 5.0
Frequency 170 82 220 153 92 58 40 15 12 18 10
Step-By-Step Explanation:
As we need the estimated probability distribution for teens spending time texting, we will be needing the total sample size.
As given in the problem statement,
<em><u>Total Sample Size = 870</u></em>
To calculate estimated probability distribution, we will convert the frequency sample into estimated probability distribution, for that:
Estimated Probability Distribution (Frequency*)=
<u><em>For Example:</em></u>
Estimated probability distribution that teens spend 0 hours texting=
Similarly
Estimated probability distribution that teens spend 0.5 hours=
Using the same formula we get:
<em><u>Hours</u></em> 0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0 4.5 5.0
<em><u>Frequency</u></em>* 0.2 0.09 0.25 0.18 0.11 0.07 0.05 0.02 0.01 0.02 0.01
(<em>Note: Frequency* is the estimated probability distribution)</em>